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The RW Physics of the Decantur of Endless Water
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<blockquote data-quote="Treebranch" data-source="post: 1638759" data-attributes="member: 21049"><p>Alright, I read what Coredump has to say, and even though I didn't check his math, it seems right given what his setup is.</p><p></p><p>The idea of the water stopping at 20 feet is just stupid...it would continue on if there were significant force. Given HOW Core set his situation up...he's dead on, the decanter has no place in the real world.</p><p></p><p>Now here's what I did! This is probably more of what you wanted. I made a few assumptions that help boost the potency of this item, though in retrospect, they make the strength check a joke...a human could NOT hold this thing and use it as a weapon.</p><p></p><p><strong>ASSUMPTIONS:</strong></p><p></p><p>The stream is 1' wide...yeah whatever, that's not gonna happen, they put that there for the game and I'm going to choose to ignore it. However, notice it doesn't say diameter, it could be a thin blast, like a setting on some garden hoses. But it doesn't matter, I'm not going to use this information.</p><p></p><p>The stream ends at 20 feet. er...what? Okay, so here's how I handled this. I just said that's if it's shooting straight UP. Again, D&D abstracts are BAD, so this is the best way I could think of to say "okay, here's WHY they say 20 feet." Keep in mind that if you point it any direction other than up, the decanter (with my math) will go a hell of a lot further.</p><p></p><p><strong>So, here's the math:</strong></p><p></p><p>To get the initial velocity, we use a simple equation:</p><p></p><p>20 = 0 + v(6) - .5*32.2*6^2 (which is position = vt and .5at^2, a = gravity in this case)</p><p></p><p>So the beauty is...the water is leaving the opening at 100 feet per second! (This is rounded, but not much.)</p><p></p><p>So now all we have to do is figure out the weight of 1 second of water. 30 gallons in 6 seconds, so 5 gallons in 1 second. Each gallon is 8.345404 pounds, so...</p><p></p><p>5*8.345404 = 41.72702 pounds</p><p></p><p>Okay, here's where an assumption has to be made again, and basically has to exist because it's a *magic* item. We have to assume that the water is initially at rest. So then it goes from 0 to 100 feet per second in 1 second. So its acceleration (the moment it leaves the decanter) is 100 ft/s^2.</p><p></p><p>Now, F = ma.</p><p></p><p>41.72702 * 100 = 4172 foot-pounds of force. Now let me put this in terms you can more easily relate to.</p><p></p><p>Don't know how much that is? Using conservation of momentum, where m1v1 = m2v2, we can see that something weighing 5 times as much as the 5 gallons of water would travel 1/5th as fast, or 20 feet per second.</p><p></p><p>So, 5 times the 5 gallons of water is 208.6 pounds. So basically, picture a 208.6 pound person running at you at 20 feet per second. Hrm, how fast is this?</p><p></p><p>20 / 1.4667 = 13.6 mph.</p><p></p><p><strong>So basically a 210 pound person is running at you fast enough so that they could do a 4 1/2 minute mile. So tell me, are you able to stop them?</strong></p><p></p><p>I'll work on the boat calculations in a bit - I'm just putting this up so you can see how poorly D&D models real life.</p></blockquote><p></p>
[QUOTE="Treebranch, post: 1638759, member: 21049"] Alright, I read what Coredump has to say, and even though I didn't check his math, it seems right given what his setup is. The idea of the water stopping at 20 feet is just stupid...it would continue on if there were significant force. Given HOW Core set his situation up...he's dead on, the decanter has no place in the real world. Now here's what I did! This is probably more of what you wanted. I made a few assumptions that help boost the potency of this item, though in retrospect, they make the strength check a joke...a human could NOT hold this thing and use it as a weapon. [B]ASSUMPTIONS:[/B] The stream is 1' wide...yeah whatever, that's not gonna happen, they put that there for the game and I'm going to choose to ignore it. However, notice it doesn't say diameter, it could be a thin blast, like a setting on some garden hoses. But it doesn't matter, I'm not going to use this information. The stream ends at 20 feet. er...what? Okay, so here's how I handled this. I just said that's if it's shooting straight UP. Again, D&D abstracts are BAD, so this is the best way I could think of to say "okay, here's WHY they say 20 feet." Keep in mind that if you point it any direction other than up, the decanter (with my math) will go a hell of a lot further. [B]So, here's the math:[/B] To get the initial velocity, we use a simple equation: 20 = 0 + v(6) - .5*32.2*6^2 (which is position = vt and .5at^2, a = gravity in this case) So the beauty is...the water is leaving the opening at 100 feet per second! (This is rounded, but not much.) So now all we have to do is figure out the weight of 1 second of water. 30 gallons in 6 seconds, so 5 gallons in 1 second. Each gallon is 8.345404 pounds, so... 5*8.345404 = 41.72702 pounds Okay, here's where an assumption has to be made again, and basically has to exist because it's a *magic* item. We have to assume that the water is initially at rest. So then it goes from 0 to 100 feet per second in 1 second. So its acceleration (the moment it leaves the decanter) is 100 ft/s^2. Now, F = ma. 41.72702 * 100 = 4172 foot-pounds of force. Now let me put this in terms you can more easily relate to. Don't know how much that is? Using conservation of momentum, where m1v1 = m2v2, we can see that something weighing 5 times as much as the 5 gallons of water would travel 1/5th as fast, or 20 feet per second. So, 5 times the 5 gallons of water is 208.6 pounds. So basically, picture a 208.6 pound person running at you at 20 feet per second. Hrm, how fast is this? 20 / 1.4667 = 13.6 mph. [B]So basically a 210 pound person is running at you fast enough so that they could do a 4 1/2 minute mile. So tell me, are you able to stop them?[/B] I'll work on the boat calculations in a bit - I'm just putting this up so you can see how poorly D&D models real life. [/QUOTE]
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