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Message: <blockquote data-quote="Scott DeWar" data-source="post: 6712761" data-attributes="member: 49929">Ok, professors, I am working on paper what you have shown me, but I have a quick question regarding a light year.given velocity of C is (Apx.) 299,792,458 M/show long is one year?is it:1. 365 days at 24 hours/ day at 60 mines per hour at 60 seconds/ minute?2. 365.25 [taking in account leap year to get closer to the astronomical year] 24 hours/ day at 60 mines per hour at 60 seconds/ minute?or 3. do we use 365.256363004 days here?[HR][/HR]also, I am guessing the ship that traveled for 100 earth years, if given enough fuel and rations to travel 100 years traveling at .9c to get to the star that is 92 light years away would only use a little over 7 years of food and fuel, returning to earth to find a whole new generation of people on earth, right?[HR][/HR]also,I saw in one of the wiki pages that velocity is not the only effect on time, gravity too.on this, if the ship is moving at .9 c, it will slow time in reference to Terra, but at 0 g it will speed time, but at an amount way less then the velocity effect isbut if there was a way to produce say a gravity of 1 earth grav, there would be no time disparity . . . Right?[HR][/HR]on communication, radio or light either one moving at C, would anything happen to the signal en-route, time wise?if the ship has traveled .9 light year, and earth sent a message aimed to intercept the ship at that point and timed to transmit 0.11...[repeat 1] Earth years down the road using the first order of approximation of 100 earth years to 3.5 ship years. Do I understand this right? I figure the ship will have traveled .035 SY. Am I right?[hr][/hr]by the way, that is correctAs for all of the various movements of the celestial bodies being factored in, that is a couple of orders of complications that is way over what I can handle at my early stages of comprehension.</blockquote>

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