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Message: <blockquote data-quote="Corathon" data-source="post: 4620497" data-attributes="member: 22238">Not that deadly. Damage is 2d6, fire rate is once per 2 rounds, maximum. It won't get into holes on the ceiling (the classic murder hole), but it will get into lateral holes (from which kobolds are sniping). Sure, but if it does get into one, the party can kill the exposed kobolds and leave. Then return the next day, rinse, repeat. I grant you that embedded iron bars inside the walls would block the passwall, but it seems unlikely that the kobolds will have an encyclopedic knowledge of every spell and have prepared countermeasures to each and every one. Yes, hefty bonuses in fact. But it doesn't matter if the kobolds save or not, they have 4 HP at most and will die anyway. According to OP, this is an AD&D1E question. There is no "search check", the spell simply works. True enough.  If the disturbed flor would be visible to the kobold's infravison, it will be visible to the thief's infravison also, so that he can avoid it in the dark. The trip wires might get him, but he has a good chance to find traps. Remember that the party in question, as posed in the OP, knows that they're hunting tricksy kobolds. Use of detect invisible (which automatically finds secret doors) and a modicum of brains means that the MUs will not be standing on/under/next to any secret doors when they cast. And there's lots of other tactics at the disposal of 9th level characters, too. Send in a conjured air elemental (which can pass through small openings, doesn't care about poison, and which the kobolds can't harm). Or have the cleric take the party ethereal (using the plane shift spell) and materialize on the other side of the kobold defenses. I actually agree with this. A party of well-prepared monsters can give much higher level PCs a run for their money. Tucker's Kobolds might even be a nasty surprise for 9th level PCs.  But a 9th level party that is prepared to fight such kobolds will stomp them. Not a fight, just a slaughter.</blockquote>

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