Menu
News
All News
Dungeons & Dragons
Level Up: Advanced 5th Edition
Pathfinder
Starfinder
Warhammer
2d20 System
Year Zero Engine
Industry News
Reviews
Dragon Reflections
White Dwarf Reflections
Columns
Weekly Digests
Weekly News Digest
Freebies, Sales & Bundles
RPG Print News
RPG Crowdfunding News
Game Content
ENterplanetary DimENsions
Mythological Figures
Opinion
Worlds of Design
Peregrine's Nest
RPG Evolution
Other Columns
From the Freelancing Frontline
Monster ENcyclopedia
WotC/TSR Alumni Look Back
4 Hours w/RSD (Ryan Dancey)
The Road to 3E (Jonathan Tweet)
Greenwood's Realms (Ed Greenwood)
Drawmij's TSR (Jim Ward)
Community
Forums & Topics
Forum List
Latest Posts
Forum list
*Dungeons & Dragons
Level Up: Advanced 5th Edition
D&D Older Editions
*TTRPGs General
*Pathfinder & Starfinder
EN Publishing
*Geek Talk & Media
Search forums
Chat/Discord
Resources
Wiki
Pages
Latest activity
Media
New media
New comments
Search media
Downloads
Latest reviews
Search resources
EN Publishing
Store
EN5ider
Adventures in ZEITGEIST
Awfully Cheerful Engine
What's OLD is NEW
Judge Dredd & The Worlds Of 2000AD
War of the Burning Sky
Level Up: Advanced 5E
Events & Releases
Upcoming Events
Private Events
Featured Events
Socials!
EN Publishing
Twitter
BlueSky
Facebook
Instagram
EN World
BlueSky
YouTube
Facebook
Twitter
Twitch
Podcast
Features
Top 5 RPGs Compiled Charts 2004-Present
Adventure Game Industry Market Research Summary (RPGs) V1.0
Ryan Dancey: Acquiring TSR
Q&A With Gary Gygax
D&D Rules FAQs
TSR, WotC, & Paizo: A Comparative History
D&D Pronunciation Guide
Million Dollar TTRPG Kickstarters
Tabletop RPG Podcast Hall of Fame
Eric Noah's Unofficial D&D 3rd Edition News
D&D in the Mainstream
D&D & RPG History
About Morrus
Log in
Register
What's new
Search
Search
Search titles only
By:
Forums & Topics
Forum List
Latest Posts
Forum list
*Dungeons & Dragons
Level Up: Advanced 5th Edition
D&D Older Editions
*TTRPGs General
*Pathfinder & Starfinder
EN Publishing
*Geek Talk & Media
Search forums
Chat/Discord
Menu
Log in
Register
Install the app
Install
Community
General Tabletop Discussion
*TTRPGs General
Venus World
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="Thomas Bowman" data-source="post: 7319654" data-attributes="member: 6925649"><p>Here is a map of the Inner System:</p><p><img src="https://orig00.deviantart.net/3cb9/f/2018/013/b/f/solar_system_inner_by_thomasbowman767-dbzxwna.png" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" />Using the Realistic Travel times for D20 Future under the column for PL6 Engine we have the following Travel Times:</p><p>Earth to the Moon (240,000 miles) 8 hours</p><p>Earth to the Sun (93,000,000 miles) 129.2 days</p><p>Earth to Mercury (56,950,000 miles 79.1 days</p><p>Earth to Venus (26,040,000 miles) 36.2 days</p><p>Earth to Mars (48,360,000 miles) 67.2 days</p><p></p><p>We get a travel rate of 3 million miles every 100 hours. (4 and 1/6 days).</p><p>30,000 miles per hour.</p><p>48,000 km per hour.</p><p>13,333 and 1/3 meters per second</p><p>Lets assume an acceleration of 1 meter per second, that is 3.7 hours to accelerate to this velocity for a total of 7.4 hours of acceleration time for a total distance traveled at an average speed of 15,000 miles per hour, of 111,000 miles the remaining miles to be covered is 129,000 miles, which at a rate of 30,000 miles per hour takes an additional 4.3 hours for a total travel time of 11.7 hours.</p><p></p><p>So using the formula: <strong><em>(Distance in miles - 111,000 miles) / 30,000 miles per hour + 7.4 hours = The travel time in hours.</em></strong></p><p>One can find the distance in squares by the distance formula by counting the horizontal number of squares between two planets on the map, and then the vertical number of squares and then applying the Pythagorean theorem Distance = square root of the sum of the vertical distance squared and the horizontal distance squared or <strong><em>Distance = (x^2 + y^2)^0.5</em></strong></p><p></p><p>A more legible map can be found at <a href="https://thomasbowman767.deviantart.com/art/Solar-System-Inner-725496454" target="_blank">https://thomasbowman767.deviantart.com/art/Solar-System-Inner-725496454</a></p><p></p><p>The positions on the map can be used as the starting positions, the map I took them from shows the positions of the planets at the beginning of the year 2013, but for game purposes, you can either find the actual positions of the planets in the year 2078 or you can just use this map as is, however you like. We have a period for each orbit, so this gives you how many degrees to advance each planet for any given time period, or you can use Kepler's law of planetary motion, which states that a planet sweeps equal areas of its orbit in equal amounts of time. Area of a circle is Area = 2 pi radius^2. The period of the orbit of each planet is found at the corners of the map. Divide the area of a circle at the planet's average distance from the Sun by its orbital period in days, and that is the area swept out by each planet in one day, now use the current distance of the planet and calculate the distance covered by that planet when it sweeps an equal area of a circle drawn at the current distance. So if te current distance is greater than average, it will travel fewer degrees in one day, if it is closer, it will cover more degree in its orbit. All orbital motion on this map is counter-clockwise. Dotted line orbits indicate that portion of the orbit is below the plane of the ecliptic.</p></blockquote><p></p>
[QUOTE="Thomas Bowman, post: 7319654, member: 6925649"] Here is a map of the Inner System: [IMG]https://orig00.deviantart.net/3cb9/f/2018/013/b/f/solar_system_inner_by_thomasbowman767-dbzxwna.png[/IMG]Using the Realistic Travel times for D20 Future under the column for PL6 Engine we have the following Travel Times: Earth to the Moon (240,000 miles) 8 hours Earth to the Sun (93,000,000 miles) 129.2 days Earth to Mercury (56,950,000 miles 79.1 days Earth to Venus (26,040,000 miles) 36.2 days Earth to Mars (48,360,000 miles) 67.2 days We get a travel rate of 3 million miles every 100 hours. (4 and 1/6 days). 30,000 miles per hour. 48,000 km per hour. 13,333 and 1/3 meters per second Lets assume an acceleration of 1 meter per second, that is 3.7 hours to accelerate to this velocity for a total of 7.4 hours of acceleration time for a total distance traveled at an average speed of 15,000 miles per hour, of 111,000 miles the remaining miles to be covered is 129,000 miles, which at a rate of 30,000 miles per hour takes an additional 4.3 hours for a total travel time of 11.7 hours. So using the formula: [B][I](Distance in miles - 111,000 miles) / 30,000 miles per hour + 7.4 hours = The travel time in hours.[/I][/B] One can find the distance in squares by the distance formula by counting the horizontal number of squares between two planets on the map, and then the vertical number of squares and then applying the Pythagorean theorem Distance = square root of the sum of the vertical distance squared and the horizontal distance squared or [B][I]Distance = (x^2 + y^2)^0.5[/I][/B] A more legible map can be found at [URL]https://thomasbowman767.deviantart.com/art/Solar-System-Inner-725496454[/URL] The positions on the map can be used as the starting positions, the map I took them from shows the positions of the planets at the beginning of the year 2013, but for game purposes, you can either find the actual positions of the planets in the year 2078 or you can just use this map as is, however you like. We have a period for each orbit, so this gives you how many degrees to advance each planet for any given time period, or you can use Kepler's law of planetary motion, which states that a planet sweeps equal areas of its orbit in equal amounts of time. Area of a circle is Area = 2 pi radius^2. The period of the orbit of each planet is found at the corners of the map. Divide the area of a circle at the planet's average distance from the Sun by its orbital period in days, and that is the area swept out by each planet in one day, now use the current distance of the planet and calculate the distance covered by that planet when it sweeps an equal area of a circle drawn at the current distance. So if te current distance is greater than average, it will travel fewer degrees in one day, if it is closer, it will cover more degree in its orbit. All orbital motion on this map is counter-clockwise. Dotted line orbits indicate that portion of the orbit is below the plane of the ecliptic. [/QUOTE]
Insert quotes…
Verification
Post reply
Community
General Tabletop Discussion
*TTRPGs General
Venus World
Top