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What should the skill list look like?
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<blockquote data-quote="tuxgeo" data-source="post: 6024254" data-attributes="member: 61026"><p><em><strong>How about those Long-Jumpers?</strong></em> Carl Lewis has jumped farther than 29 feet (8.87 m) legally. In 5E Next so far, your long jump distance in feet is equal to your STR score (if you get a 10-foot walking start), so Carl Lewis must have had a STR score of 29 at that time, right? <em>Well, NO: I don't think so.</em> That would have his result be purely a matter of strength, so his extensive training in the event would have had no effect. (Why do people even bother training, anyway, if it has no effect?) </p><p></p><p>There's something wrong there. Training should count for something. </p><p>One possibility is this: STR score <strong>plus</strong> (d20-roll divided by 4, round down) <strong>plus </strong>"Jump" skill training +3. So: STR score 20 + (20/4 = 5) + 3 = 28 feet on a natural 20. That models long-jumping better, though not perfectly, and lets Carl Lewis at least come to within a foot or so of what he could actually do in the real world. (And if you allow him to take a Skill Focus feat for a +1 feat bonus, that would get him to 29 feet, within an inch or so of his personal best.)</p><p></p><p>I don't believe that a +3 for Skill Training and a +1 for Skill Focus would break the DC math too badly.</p><p></p><p>However, that gives a fairly tight range of results: minimum 24 feet, maximum 29 feet. That's because the d20-roll was divided by 4, but the STR score wasn't. To balance that out, divide each one by 2, instead. </p><p></p><p>Say that anyone can jump 5 feet with a walking start, so give them that as a base amount (sort of like AC starts at 10 with no armor). Divide <em>both</em> the STR score and the d20 roll by 2 (round down). Our Olympic PC long jumper with STR 20 then jumps: </p><p>(Nat-20): 5 + (20/2 = 10) + (20/2 = 10) + 3 (training) + 1 (focus) = 29. </p><p>(Nat-1): 5 + (20/2 = 10) + (1/2 = 0) + 3 (training) + 1 (focus) = 19. That's still a good jump befitting the Strength, but nowhere near competitive.</p><p></p><p>Edit: Another thought: </p><p>Instead of giving everybody a flat +5 to start out with, add the PC's STR <em>modifier</em> into the mix. </p><p></p><p>Our STR-20 Olympian PC then jumps: </p><p>(Nat-20): 5 (STR mod.) + (20/2 = 10) + (20/2 = 10) + 3 (training) + 1 (focus) = 29.</p><p>(Nat-1): 5 (STR mod.) + (20/2 = 10) + (1/2 = 0) + 3 (training) + 1 (focus) = 19.</p><p></p><p>However, an untrained bookworm-type wizard with STR 8 jumps: </p><p>(Nat-20): -1 (STR mod.) + (8/2 = 4) + (20/2 = 10) = 13. </p><p>(Nat-1): -1 (STR mod.) + (8/2 = 4) + (1/2 = 0) = 3.</p></blockquote><p></p>
[QUOTE="tuxgeo, post: 6024254, member: 61026"] [I][B]How about those Long-Jumpers?[/B][/I] Carl Lewis has jumped farther than 29 feet (8.87 m) legally. In 5E Next so far, your long jump distance in feet is equal to your STR score (if you get a 10-foot walking start), so Carl Lewis must have had a STR score of 29 at that time, right? [I]Well, NO: I don't think so.[/I] That would have his result be purely a matter of strength, so his extensive training in the event would have had no effect. (Why do people even bother training, anyway, if it has no effect?) There's something wrong there. Training should count for something. One possibility is this: STR score [B]plus[/B] (d20-roll divided by 4, round down) [B]plus [/B]"Jump" skill training +3. So: STR score 20 + (20/4 = 5) + 3 = 28 feet on a natural 20. That models long-jumping better, though not perfectly, and lets Carl Lewis at least come to within a foot or so of what he could actually do in the real world. (And if you allow him to take a Skill Focus feat for a +1 feat bonus, that would get him to 29 feet, within an inch or so of his personal best.) I don't believe that a +3 for Skill Training and a +1 for Skill Focus would break the DC math too badly. However, that gives a fairly tight range of results: minimum 24 feet, maximum 29 feet. That's because the d20-roll was divided by 4, but the STR score wasn't. To balance that out, divide each one by 2, instead. Say that anyone can jump 5 feet with a walking start, so give them that as a base amount (sort of like AC starts at 10 with no armor). Divide [I]both[/I] the STR score and the d20 roll by 2 (round down). Our Olympic PC long jumper with STR 20 then jumps: (Nat-20): 5 + (20/2 = 10) + (20/2 = 10) + 3 (training) + 1 (focus) = 29. (Nat-1): 5 + (20/2 = 10) + (1/2 = 0) + 3 (training) + 1 (focus) = 19. That's still a good jump befitting the Strength, but nowhere near competitive. Edit: Another thought: Instead of giving everybody a flat +5 to start out with, add the PC's STR [I]modifier[/I] into the mix. Our STR-20 Olympian PC then jumps: (Nat-20): 5 (STR mod.) + (20/2 = 10) + (20/2 = 10) + 3 (training) + 1 (focus) = 29. (Nat-1): 5 (STR mod.) + (20/2 = 10) + (1/2 = 0) + 3 (training) + 1 (focus) = 19. However, an untrained bookworm-type wizard with STR 8 jumps: (Nat-20): -1 (STR mod.) + (8/2 = 4) + (20/2 = 10) = 13. (Nat-1): -1 (STR mod.) + (8/2 = 4) + (1/2 = 0) = 3. [/QUOTE]
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