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<blockquote data-quote="Anth" data-source="post: 6453503" data-attributes="member: 9636">3E had a strange CR/xp-table (I liked it, but it was strange). As you gained level the monsters actually was worth less xp, until they were so insignificant that you gained zero xp to kill them.So what happend if a level 9 knight went adventuring with his level 1 squire? You took the average level of the party (1 + 9)/ 2 = 5. Meaning that the knight actually got more xp for monsters and the squire got less xp. The reasoning was that the knight got more xp because had to spend time to keep his squire alive, and the squire got less xp as he got help from the powerful knight.In the 3E FRCS there was an optional rule that I liked and used. Instead of using average level for calculating xp, you used the actual character level. So instead that the knight and squire above got half xp each as they were a level 5 party, the knight got half xp from a party containing 2 level 9 characters, and the squire got half xp from a party containing 2 level 1 characters. Meaning that the squire catched up quite fast.Of course this required some extra math, but for me it was worth it.This is my solution for a similar mechanic in 5E:The highest member in the party gain as many parts of the xp as his level. Characters with lower level gain more parts equal tho the level difference.Example:A party contain 3 PCs at level 3, 4, 5.The level 5 PC, being higest level gain 5 parts.The level 4 PC, being one level lower gain one more part: 6 parts.The level 3 PC, being two levels lower gain two more parts: 7 parts.Together they have 5 + 6 + 7 = 18 parts.Divide all gained xp with 18, then give the PCs their parts.</blockquote>

[QUOTE="Anth, post: 6453503, member: 9636"] 3E had a strange CR/xp-table (I liked it, but it was strange). As you gained level the monsters actually was worth less xp, until they were so insignificant that you gained zero xp to kill them. So what happend if a level 9 knight went adventuring with his level 1 squire? You took the average level of the party (1 + 9)/ 2 = 5. Meaning that the knight actually got more xp for monsters and the squire got less xp. The reasoning was that the knight got more xp because had to spend time to keep his squire alive, and the squire got less xp as he got help from the powerful knight. In the 3E FRCS there was an optional rule that I liked and used. Instead of using average level for calculating xp, you used the actual character level. So instead that the knight and squire above got half xp each as they were a level 5 party, the knight got half xp from a party containing 2 level 9 characters, and the squire got half xp from a party containing 2 level 1 characters. Meaning that the squire catched up quite fast. Of course this required some extra math, but for me it was worth it. This is my solution for a similar mechanic in 5E: The highest member in the party gain as many parts of the xp as his level. Characters with lower level gain more parts equal tho the level difference. Example: A party contain 3 PCs at level 3, 4, 5. The level 5 PC, being higest level gain 5 parts. The level 4 PC, being one level lower gain one more part: 6 parts. The level 3 PC, being two levels lower gain two more parts: 7 parts. Together they have 5 + 6 + 7 = 18 parts. Divide all gained xp with 18, then give the PCs their parts. [/QUOTE]

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