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What's wrong with high-level/epic play?
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<blockquote data-quote="Upper_Krust" data-source="post: 4651319" data-attributes="member: 326"><p>Howdy Runestar! <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":)" title="Smile :)" data-smilie="1"data-shortname=":)" /></p><p></p><p></p><p></p><p>Okay, its been a while since I went over it, but basically forget about EL until after you pick.</p><p></p><p>The number of PCs and their average level.</p><p></p><p>Lets say you have one PC of 10th-level. A 50/50 challenge for him will be a CR 10-11 Monster.</p><p></p><p>Lets say you have four PCs of 10th-level fighting the same CR 10-11 monster. With four PCs the EL of the CR 10-11 monster is reduced by 4. So it becomes a moderate challenge using 25% of their resources.</p><p></p><p>So the basic thing to remember is that EL (in this system) has nothing to do with the level of your PCs.</p><p></p><p>EL is a method for determining what the relative difference will be for your PCs if you add/subtract either monsters or PCs to the equation.</p><p></p><p>So. </p><p></p><p>1. Take the average PC level. </p><p></p><p>Lets say they average 50th-level.</p><p></p><p>2. That determines the average CR range. </p><p></p><p>The range (Level 50 falls under) is CR 48-55</p><p></p><p>3. On the Table what is the EL next to that CR.</p><p></p><p>CR 48-55 = EL 23</p><p></p><p>4. Then modify that EL by the number of PCs</p><p></p><p>Lets say you have 7 PCs, that means you need monsters of EL +5 (EL 28 in this case) to give the PCs a 50/50 challenge, EL 26 would be a tough challenge, EL 24 a moderate challenge and so on.</p><p></p><p>For a single monster we look at EL 28 on the Table and see that it coresponds to CR 112-127.</p><p></p><p>For multiple monsters of the same level we modify EL just like we did for the PCs. For instance a 50/50 challenge for those PCs would be between 32-47 Balors. Normal Balor = CR 20 = EL 18. 32-47 Balors are +10 EL, which gives us EL 28.</p><p></p><p>However, while (I hope) that explains v5, I should point out that all those calculations are incorrect where (the more accurate) v6 is concerned - basically because I made a flaw in the relationship between CR and EL. The initial equation was CR x2 = EL +4 (and thus CR x1.5 = EL +2).</p><p></p><p>But the correct equation is more like CR x2 = EL +8 (and thus CR x1.5 = EL +4).</p></blockquote><p></p>
[QUOTE="Upper_Krust, post: 4651319, member: 326"] Howdy Runestar! :) Okay, its been a while since I went over it, but basically forget about EL until after you pick. The number of PCs and their average level. Lets say you have one PC of 10th-level. A 50/50 challenge for him will be a CR 10-11 Monster. Lets say you have four PCs of 10th-level fighting the same CR 10-11 monster. With four PCs the EL of the CR 10-11 monster is reduced by 4. So it becomes a moderate challenge using 25% of their resources. So the basic thing to remember is that EL (in this system) has nothing to do with the level of your PCs. EL is a method for determining what the relative difference will be for your PCs if you add/subtract either monsters or PCs to the equation. So. 1. Take the average PC level. Lets say they average 50th-level. 2. That determines the average CR range. The range (Level 50 falls under) is CR 48-55 3. On the Table what is the EL next to that CR. CR 48-55 = EL 23 4. Then modify that EL by the number of PCs Lets say you have 7 PCs, that means you need monsters of EL +5 (EL 28 in this case) to give the PCs a 50/50 challenge, EL 26 would be a tough challenge, EL 24 a moderate challenge and so on. For a single monster we look at EL 28 on the Table and see that it coresponds to CR 112-127. For multiple monsters of the same level we modify EL just like we did for the PCs. For instance a 50/50 challenge for those PCs would be between 32-47 Balors. Normal Balor = CR 20 = EL 18. 32-47 Balors are +10 EL, which gives us EL 28. However, while (I hope) that explains v5, I should point out that all those calculations are incorrect where (the more accurate) v6 is concerned - basically because I made a flaw in the relationship between CR and EL. The initial equation was CR x2 = EL +4 (and thus CR x1.5 = EL +2). But the correct equation is more like CR x2 = EL +8 (and thus CR x1.5 = EL +4). [/QUOTE]
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