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Why do guns do so much damage?
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<blockquote data-quote="Ovinomancer" data-source="post: 8301544" data-attributes="member: 16814"><p>This is very messy. To start, the units don't work. You took seconds divided by meters per second, which ends up as seconds squared per meter, and then multiplied by meters for seconds squared.</p><p></p><p>What you wanted to do was assume constant acceleration (reasonable here) and look at d=1/2at^2, and v=at, so subbing you get d =1/2vt. Time will be t=2d/v, or 2(.4m)/271m/s (for arguments sake, I'm taking this number, although there's strong evidence to the different). This is 3ms, or 0.003seconds. Going back through, that's an acceleration of 90.3km/s or so.</p><p></p><p>Plugging that into F=ma and you get 0.013kg(90,300m/s^2)= 1174N.</p><p></p><p>Thing is that's a tiny bullet. 13 grams is a bullet almost a 1/3 the size of the musket. This isn't born out by visuals, or the record, where pistols fired shot about the same size as the muskets, until the advent of the revolver, at least.</p><p></p><p>Not really. Look at the formulas and see what mass and velocity and acceleration do. Mass is the same in both -- double it and you double both. Velocity and acceleration are very different beasts, though, and you've seen in the calculations that to get a velocity of X, the acceleration for a bullet to get there is orders of magnitude higher. So, on that alone, it makes a lot of sense that a bullet's momentum is low but it's force is high -- the difference between v and a is large. For a sword, though, v and a are closer, so the momentum and force are closer -- same order of magnitude at least.</p><p></p><p>I'm not sure you can read those graphs that way -- it doesn't label either, and their gel does an odd thing in how it sustains visible damage much wider than the permanent wound track. Normal ballistic gel doesn't do this because it's highly elastic and so you can only see the scope of the temporary expansion in slow mo. So, I'm not exactly convinced their graph (which closely matches the visible damage done) is actually the scope of the temporary cavity rather than where a poorly mixed ballistic gel sustained damage due to tearing. It's not at all clear from that video (and the second one you link has properly mixed gel and doesn't sustain damage outside the permanent wound track).</p><p></p><p>I cited the actual ballistic data for a .44 magnum, which your cited article said was a high cavity weapon, and it is in the ballpark of the numbers being calculated for flintlock pistols here. The number I calculated, and which was the same using your cited calculators (because I was using the same formulas), are nearly identical for a musket. This makes a musket a very deadly weapon, doing massively more damage than you expected. The pistol, even accounting for the lower velocity you want, is still very dangerous, with numbers close. The only cite in thread that showed pistol data lists a flintlock at very near that same number for the .44 (and this makes sense once you account for an actual larger caliber rather than the odd very low bullet size you calculated). Flintlocks were very dangerous weapons, and not far behind or on par with some modern weapons in power (if not accuracy or reliability). It's only when you get to the high-power stuff that modern firearms (and we're talking rifles here) really get away from them. The size of the shot and the power of the weapon meant that it was very, very damaging.</p><p></p><p>And, again, this has nothing at all to do with how you represent firearms in game.</p></blockquote><p></p>
[QUOTE="Ovinomancer, post: 8301544, member: 16814"] This is very messy. To start, the units don't work. You took seconds divided by meters per second, which ends up as seconds squared per meter, and then multiplied by meters for seconds squared. What you wanted to do was assume constant acceleration (reasonable here) and look at d=1/2at^2, and v=at, so subbing you get d =1/2vt. Time will be t=2d/v, or 2(.4m)/271m/s (for arguments sake, I'm taking this number, although there's strong evidence to the different). This is 3ms, or 0.003seconds. Going back through, that's an acceleration of 90.3km/s or so. Plugging that into F=ma and you get 0.013kg(90,300m/s^2)= 1174N. Thing is that's a tiny bullet. 13 grams is a bullet almost a 1/3 the size of the musket. This isn't born out by visuals, or the record, where pistols fired shot about the same size as the muskets, until the advent of the revolver, at least. Not really. Look at the formulas and see what mass and velocity and acceleration do. Mass is the same in both -- double it and you double both. Velocity and acceleration are very different beasts, though, and you've seen in the calculations that to get a velocity of X, the acceleration for a bullet to get there is orders of magnitude higher. So, on that alone, it makes a lot of sense that a bullet's momentum is low but it's force is high -- the difference between v and a is large. For a sword, though, v and a are closer, so the momentum and force are closer -- same order of magnitude at least. I'm not sure you can read those graphs that way -- it doesn't label either, and their gel does an odd thing in how it sustains visible damage much wider than the permanent wound track. Normal ballistic gel doesn't do this because it's highly elastic and so you can only see the scope of the temporary expansion in slow mo. So, I'm not exactly convinced their graph (which closely matches the visible damage done) is actually the scope of the temporary cavity rather than where a poorly mixed ballistic gel sustained damage due to tearing. It's not at all clear from that video (and the second one you link has properly mixed gel and doesn't sustain damage outside the permanent wound track). I cited the actual ballistic data for a .44 magnum, which your cited article said was a high cavity weapon, and it is in the ballpark of the numbers being calculated for flintlock pistols here. The number I calculated, and which was the same using your cited calculators (because I was using the same formulas), are nearly identical for a musket. This makes a musket a very deadly weapon, doing massively more damage than you expected. The pistol, even accounting for the lower velocity you want, is still very dangerous, with numbers close. The only cite in thread that showed pistol data lists a flintlock at very near that same number for the .44 (and this makes sense once you account for an actual larger caliber rather than the odd very low bullet size you calculated). Flintlocks were very dangerous weapons, and not far behind or on par with some modern weapons in power (if not accuracy or reliability). It's only when you get to the high-power stuff that modern firearms (and we're talking rifles here) really get away from them. The size of the shot and the power of the weapon meant that it was very, very damaging. And, again, this has nothing at all to do with how you represent firearms in game. [/QUOTE]
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