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I made a formula for the chances of success. It does not have any logic for natural 1s or natural 20s, just the chance of hitting. 1d20 = (21-n)/20 2d20 = 1-((n-1)/20)^2 (n is the roll needed to hit) Here is the table of odds below: ToHit 1d20 2d20 1 100.0% 100.00% 2...