I was reading a thread on rpg.net where they are reading through the pf2e core rule book a chapter at a time and a question was asked about how to calculate XP awards for different sized parties. The only answer given was to try and reverse engineer it from encounter difficulty tables which is annoying to do. So I figured I would post a better way to do it in case anyone here was also wondering how to do this:
First sum up the XP from defeated creatures/hazards using table 10-8. Then divide that by the number of players and multiply by 4. This is the amount of XP each player receives (you can round to the nearest 10 if desired).
In other words: the party divides the xp into individual contributions and each pc then receives an amount of XP equal to four of their individual contributions (a party of four).
Example: say a party of six defeats four level-1 monsters. That’s 120 XP total, 20 per player, and 80 for four players. So each player gets 80 XP.
First sum up the XP from defeated creatures/hazards using table 10-8. Then divide that by the number of players and multiply by 4. This is the amount of XP each player receives (you can round to the nearest 10 if desired).
In other words: the party divides the xp into individual contributions and each pc then receives an amount of XP equal to four of their individual contributions (a party of four).
Example: say a party of six defeats four level-1 monsters. That’s 120 XP total, 20 per player, and 80 for four players. So each player gets 80 XP.