ssampier said:I appreciate the correction. I am confused because all dice are cast at the same time. The first die is not the comparison; each die has a 1/4 independent chance of obtaining that same number.
But you aren't trying to figure out the probability of all the dice getting a *particular* number, you're trying to figure out the probability of them all getting the same number, without specifying what that number is. The timing of the rolls is irrelevant -- just arbitrarily pick a die to call the first. "All four dice come up the same" is equivalent to "whatever the first die got, the other three all got that."
ssampier said:I must of missed that. I thought the heroes were d4s and the demon die was a d6.
Yeah, me too. I think I hastily read "four six-sided dice" as "four-sided dice".
So this simplifies the calculation. The probability that the hero dice will all come up the same is (1/6)^3=1/216=0.005. The probability that a particular hero die will not match the demon die is 5/6; the probability that none of them will match the demon is (5/6)^4=625/1296=0.483.
ssampier said:In any case, I forgot the AND/Or rule. I read some statistics forums online and I think I understand the difference now.
in this case: 1 - (5/6)^n
...where n is the number of dice. That is the probability that at least one of the dice lands on a specified number (e.g. whatever number the demon die lands on).