frankthedm
First Post
Seven for Four sounds exacly like would become two for one when simplified to the same standard of three for two.carborundum said:For a 2x2x2 cube, the longest diagonal has one side 2 long and one 2.8. This works out at about 3.5 (3.46) - what would you call that? A cost of seven for four diagonal 3D hops, I guess.
If it costs 2 squares of area* to travel from A to H, which of the above 3 3D areas would best aproximate that.carborundum said:Sorry, not quite sure what you mean with the "two furthest" thing, Mr. Frank. I'm glad you liked the argument though![]()
*In the same way going diagonaly across a square costs one then 2, one then 2.