tarchon
First Post
SD isn't a measurement of the width of any peak, and it's really not even a measurement. If you're measuring something, it's technically an estimator of a parameter, not the parameter itself. SD is the square root of the variance, the expectation of the square of the deviation from the mean (also called the 2nd central moment)Umbran said:
Well, the dsitribution for a fair single die should be completely flat. Standard deviations are intended to measure the width of a peak. The results of a d20 should have no peak whatsoever. So Standard deviation will probably fail to be a good measure.
sqrt(E[(x-μ )<sup>2</sup>]). With certain unimodally peaked distributions like the normal, this corresponds to the width of the peak, but it's neither the definition nor the underlying sense of what SD is. As the name roundaboutly implies, it represents how much the random variable or process tends to deviate from the mean.
Uniform distributions have it and they've got quite a lot of it.
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