Multiclass Initiator: how do you interpret it?

[Egres]

If you are a multiclass martial adept, and you learn a new maneuver attaining a new level in a martial adept class, determine your initiator level by adding together your level in that class + 1/2 your levels in all other classes. This process applies to all of a character's levels, whether they are in martial adept classes or other classes.

Now, the question is: if you are a character with three or more classes, (say, a 10 Warblade/1 Swordsage/1 Crusader), what is your Initiator level in each of these classes?

1/2 of each class+your level ( 1/2 Swordsage + 1/2 Crusader+ 10 Warblade=Warblade 10)

or

1/2 the sum of all the other classes+your level ( 1/2 (Swordsage + Crusader) + 10 Warblade=Warblade 11?

 

[Jhaelen]

1/2 the sum of all the other classes+your level ( 1/2 (Swordsage + Crusader) + 10 Warblade=Warblade 11?

That's the one. Add up all levels in other classes, then divide by two.

 

[Engilbrand]

Warblade=11
Swordsage=6
Crusader=6

 

[AllisterH]

Hmm...I was under the impression that you rounded down for each class.

Thus a warblade 10/swordsage 1/crusader 1 would have the following IL

WB IL 10/ SS IL 6/Crus IL 6.

Given that this is how "1/2 your level" is used in pretty much every other aspect of the rules.

 

[hong]

In the spirit of how fractions and multiclassing usually works, I'd round down for each class.

 

[Engilbrand]

I was under the impression that you added up all of the other classes together and then halved that number. It makes more sense.

 

[hong]

It would also make more sense to do it that way for things like saves and BAB. While that's not RAW, it would make a fine house rule.

What?

 

[blargney the second]

I was under the impression that you added up all of the other classes together and then halved that number. It makes more sense.

That's the way I run it.