Pretrifcation

dpflutie9 · Mar 28, 2004

Need to know where the find the rules for the weight of a petrified character. Wizard was peftrified by a Gorgan. Thanks

dcollins · Mar 28, 2004

In a physics book?

Derulbaskul · Mar 28, 2004

I would just multiply the character's weight by four unless someone shows up who knows the density of "normal" rock (and I know there is no such thing as "normal").

WizWrm · Mar 28, 2004

Well, your best bet would be to model it after petrified wood. Petrified wood, after a brief google search, is apparently 1-15% organic matter and the rest is mineral matter, according to this site, which also names petrified wood as SiO2. SiO2, or silicon dioxide, according to Wikipedia has a density of 2600 kg/m^3.

So, I'd go for multiplying 2600 by the wizard's volume in cubic meters, then multiplying that by 0.9 and adding 10% of the wizard's normal weight, to get his weight, in kilograms, while petrified.

...er, why did you edit your original post to add typos?

nameless · Mar 28, 2004

2600 kg/m^3 roughly translates to 2.6 g/cm^3, unless I'm mistaken (from measurements I've taken before, that sounds right). That's about 2.6 times as dense as water, and the human body is pretty close in density to water, close enough to fudge it, at any rate. If you multiply his weight by 2.5 to 3.0, you should get a pretty good estimate of how much he would weigh as stone.

nimisgod · Mar 28, 2004

I think the Stone Body spell (from OA) multiplies your weight by a factor of eight. Petrification is very similar so...

Tatsukun · Mar 28, 2004

As it would happen, my brother just installed a statue of a full-size man. he reports that it weighed 961 Lb. (I love internet chat, it's so fast!)

So, if we are going by the "multiply by 4" method, the origional guy would have weighed 240.25 Lb. That's a little heavy, but I think the "multiply by 4 rule" works for me.

-Tatsu