D&D 3E/3.5 v4: Challenge Ratings pdf (3.5 compatible)


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(level x (level-1))/2 x 1000

One of level and (level -1) will be even, so you will never have to worry about rounding when you divide by 2.

For mental arithmatic, take level and (level -1), divide the even one by 2, multiply, then add 000 to the end.

So for level 10, you consider 10 and 9, divide 10 by 2 to get 5, multiply by 9 to get 45, and add 000 to get 45 000.
 






Hi all! :)

Cheiromancer said:
(level x (level-1))/2 x 1000

One of level and (level -1) will be even, so you will never have to worry about rounding when you divide by 2.

For mental arithmatic, take level and (level -1), divide the even one by 2, multiply, then add 000 to the end.

So for level 10, you consider 10 and 9, divide 10 by 2 to get 5, multiply by 9 to get 45, and add 000 to get 45 000.

Impeesa said:
500 * level * (level - 1) is the minimum xp required to be at that level. Simplify when you integrate, people. :p

I like both of those thanks guys.

I think I am on the verge of solving the Treasure problem. Though I believe our old friend Anubis wants to comment on this. He perhaps believes he has a better system and wants to get some feedback.

My new Treasure Rules are currently (with nods to Impeesa):

(90*CR +1*CR) +30

I'll amend the Table in v5 (for those who know that Table).

If people think Anubis ideas have merit then I will incorporate them, otherwise I can go ahead tomorrow with v5. Give Anubis a fair shout though.
 


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