dcollins
Explorer
Nathan said:The denominator has to be d^n, not n^d, of course...
Right, I came up with that last night, thanks for noting that.
My program to verify this currently gives at least sane results for the case of 2Dd drop 1. However, other cases still don't appear correct, currently shows averages of:
2d1 drop 1 --> 1.000000
2d6 drop 1 --> 4.472222
3d6 drop 1 --> 3.402778
4d6 drop 1 --> 1.787809
5d6 drop 2 --> 3.379372
3d1 drop 1 --> 5.000000
I don't know if you have further comment on this, or I may have to start scratching out a 3dD drop 1 case by hand. Current .c program attached below.