wuyanei said:Hmm... KarinsDad, you have a point. We should use the 'Average point-buy value' instead of 'The point-buy value of a character with all average scores'.
...
6.3397 x 6 = 38.0382 ...so a 38 pt point-buy might be a better representation of 5d6 drop two lowest.
BTW, I'm rather curious on how you came to the 39.6 pt number. Would you mind sharing your calculation method?
Thanks for replying!
Yanei Wu
I might have errors in mine. I double checked, but did not quadruple check.
But, you appear to have rounding errors in yours. For example, there is only one three possible. You need to roll 5 1s to get it. So, the odds are 1/7776 or 0.0001286. You have it listed as 0.01% (or 0.0001).
I did a spreadsheet of all possible combinations (yes, that took me over 50 cut and pastes to create 7776 rows and took 15 minutes). Not the brightest idea, but I do not have C++ on this computer and am an Excel novice.
I then did a =SUM(B2:F2)-SMALL(B2:F2,1)-SMALL(B2:F2,2) type equation for each row, summing it all up and dropping the smallest two.
I then did a =COUNTIF(H2:H7777,3), =COUNTIF(H2:H7777,4), etc. to figure out how many of each I had. I then multiplied this by the individual point count for each one, summed them up, and divided by 7776.
And actually, my average is 13.43017, slightly off yours as well. So, I could well have errors.
I figure we are in the ballpark though.