[d20] What don't you know? (free pdf books)
- Thread starter TheLe
- Start date
As long as we're grasping at straws...
Can you only answer Red or Green in Common or can you use other languages? If so, Red in common means that yours is red and the person in front of you is red as well. If you say red in Gnomish, yours is red but the person in front of you is green.
Can you only answer Red or Green in Common or can you use other languages? If so, Red in common means that yours is red and the person in front of you is red as well. If you say red in Gnomish, yours is red but the person in front of you is green.
The Answer
So, scenario 1:
Adventurer 1 says the color in front of him.
Adventurer 2 is saved.
Adventurer 3 says the color in front of him... etc.
5 people are guaranteed salvation.
Scenario 2:
Adventurer 1 says red if 2 and 3 have matching colors. Green otherwise.
Adventurer 2 says the color in front of him if 1 said red.
Adventurer 3 says what 2 said if 1 said red.
6 people are guaranteed salvation.
The real answer.
Adventurer 1 takes a look ahead and seed 9 flames ahead of him. If there are an even amount of red flames, he says red. If there are an odd amount, he says green.
Adventurer 2 looks ahead. If adventurer 1 said red, indicating an even amount, and 2 sees an odd amount, he knows that his flame is red.
Adventurer 3 looks ahead. If 1 said red, 2 said red, he now knows there are an odd amount of red flames left. If he sees an even amount, he knows he is red. Do I need to explain this further?
So, scenario 1:
Adventurer 1 says the color in front of him.
Adventurer 2 is saved.
Adventurer 3 says the color in front of him... etc.
5 people are guaranteed salvation.
Scenario 2:
Adventurer 1 says red if 2 and 3 have matching colors. Green otherwise.
Adventurer 2 says the color in front of him if 1 said red.
Adventurer 3 says what 2 said if 1 said red.
6 people are guaranteed salvation.
The real answer.
Adventurer 1 takes a look ahead and seed 9 flames ahead of him. If there are an even amount of red flames, he says red. If there are an odd amount, he says green.
Adventurer 2 looks ahead. If adventurer 1 said red, indicating an even amount, and 2 sees an odd amount, he knows that his flame is red.
Adventurer 3 looks ahead. If 1 said red, 2 said red, he now knows there are an odd amount of red flames left. If he sees an even amount, he knows he is red. Do I need to explain this further?
I think I have the answer. The ten people agree as follows:
First person to choose counts the number of a certain color of light (red of green) in front of him, and then lets the others know what the count was in terms of 'odd' or 'even'. For example, green is the agreed color to count. The first person counts the number of green flames, and indicates whether it is odd or even by agreement of his selection red=odd and green=even.
So, if the first person counts green flames and states red, then there is an odd number of green flames in front of him. The second person then counts the number of green flames in front of him and can then infer whether his flame is green or red. So, if he counts an odd number, his flame is red. If he counts even, his flame is green. The third and subsequent people all take note of the odd or even designation, and change that every time somebody from the second person onwards states a green flame. So if a person states green, the odd changes to even or even changes to odd. Not the best explanation since I'm in a hurry, but I believe it works.
That it?
Pinotage
First person to choose counts the number of a certain color of light (red of green) in front of him, and then lets the others know what the count was in terms of 'odd' or 'even'. For example, green is the agreed color to count. The first person counts the number of green flames, and indicates whether it is odd or even by agreement of his selection red=odd and green=even.
So, if the first person counts green flames and states red, then there is an odd number of green flames in front of him. The second person then counts the number of green flames in front of him and can then infer whether his flame is green or red. So, if he counts an odd number, his flame is red. If he counts even, his flame is green. The third and subsequent people all take note of the odd or even designation, and change that every time somebody from the second person onwards states a green flame. So if a person states green, the odd changes to even or even changes to odd. Not the best explanation since I'm in a hurry, but I believe it works.
That it?
Pinotage
TheLe
First Post
interwyrm said:
AND WE HAVE A WINNER!
That is absolutely correct. In the hour you have before the Necromancer returns, you all agree that the first person will always call out the color that is in an "even" amount.
This means that he always has a 50% chance of living or dying. In this case, going first sucks.
As long as the people in front can properly keep track of what the previous people said, they have a 100% chance of survival.
The most difficult is the last person, who must keep track of all the answers from the previous nine.
interwyrm, email me and pick your prize!
Sorry pinotage. Missed it by 2 minutes...
CONGRATS ALL!
~Le
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Technically... that last question would also work if you called out whichever color you saw more of...
Also... I wonder if pinotage likes green better than red. Why did I choose red if red is even, and he said green if green is even. (Which amounts to being exactly the same thing.)
Also... I wonder if pinotage likes green better than red. Why did I choose red if red is even, and he said green if green is even. (Which amounts to being exactly the same thing.)
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didn't think that out too far did I? Oh well.Similar Threads
