Blue
Ravenous Bugblatter Beast of Traal
I think you are mistaken about X Damage prevents 4Y Monster Damage.
To start consider a big solo monster. It has 200 hp normally. It does 30 damage a turn. If it normally lasts 4 turns then it will do 120 damage total. Consider if we halved its hp and doubled its damage. It would last 2 turns and do 60 a turn. That's 120 damage total.
If it lasts 4 turns (2 with half hp) turns that means we are doing 50 damage a turn to it.
Now consider the same monster split into 2 different monsters. Each has 100 hp and does 15 damage a turn.
It will take you 2 rounds to kill each monster. Round 1 you take 30 damage. Round 2 you take 30 damage. Round 3 You take 15 damage. Round 4 you take 15 damage. Total damage 90.
Now consider halving their hp and doubling their damage. Round 1 you take 60 damage. Round 2 you take 30 damage. That's 90 damage take.
So, I'm not seeing the same amount of damage causing 4 times the damage reduction by halving monster hp and doubling monster damage.
Because damage dealt doesn't always perfectly equal damage needed to kill a creature and because of whole goes first initiative, the number can't be anything but an estimation in practice. That doesn't change the theory behind it.
Let's reduce this to it's simplest form so I can show an example. But of course my example is contrived - I fully agree that it's an approximation in actual play.
2 HP creatures that do 2 damage. And the damage we're looking at doing is even so it always kills. (1 HP wouldn't be able to be divided in half.)
If in 1 round you do 10 HPs of damage, you kill 5 and that would have done 10 HPs of damage back in the same round.
Now let's take 1 HP creatures that does 4 HPs of damage.
In one round you do 10 HPs of damage. You kill 10 of them. They would have done 40 HPs back in the same round.
40 HP return damage vs. 10 HPs - that's the 4:1 I'm talking about.