MoonZar said:
Thanks you, some people say good thing. But this doesn't have a clear answer how much time it should take to dig...
Well, in that case, I'll do the math for you.
Let's assume that everything I said in that thread is true.
ME said:
From the 3.5 SRD:
Stone: Hardness 8; 15 HP / Inch
These hit points are for a 5' by 5' section. So, a 5' by 5' by 5' cube of stone has 900 hitpoints.
Buy a couple adamantine picks, and you'll be on your way through raw stone in no time.
Also ME said:
A heavy pick isn't a mining tool, it's an instrument of war - and a one-handed one, at that.
A miner's pick would be something more like:
Two-handed Improvised Weapon; 1d10 / 1d12 / x2; 12 lbs.; Piercing
So, we'll assume you've got a normal, human miner: Commoner 1, Strength 10, with a mining pick.
A 5'x5'x5' section of wall has hardness 8, 900 hitpoints.
As a full-round action, he can automatically hit a stationary object. When doing so, he does 1d12 points of damage. On a roll of 1-8, he fails to overcome the hardness. On a roll of 9-12, he does damage.
The expected damage dealt to the wall, then, can be expressed as:
Damage / Round / Miner = Chance to Hit * Average Damage
Change to Hit = 1
Average Damage = Average (0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 3, 4) = .833333
Damage / Round / Miner = .833333
Therefore, the time needed to cut through a single 5' cube of stone is:
Time = Hit Points / ((Damage / Round / Miner) * (# of Miners))
A single miner, then, can cut through a single 5' cube of stone in:
Time = 900 / (.83333 * 1) = 1080 rounds = 108 minutes = 1.8 hours
A single half-orc miner (Strength bonus +1) can do the same in 1.2 hours.
Note that this is greater than one hour of constant, backbreaking labor - they are, literally, pounding stone. As such, you might consider them to be swinging every other round, which doubles the time required.