Little help with CR/EL

[Magic Missile]

Right, just checking I'm doing this right...

Six kobolds, individual CR 1/6. But there are six of them, so I add on +6 to the overall EL (as per the table in d20 modern)? Giving an EL of 6 1/6. Assuming it's a bog standard combat, no special circumstances etc. I leave this figure as it is, then round down to EL 6.

Is this right? EL 6 sounds tremendously high for 6 kobolds.. and the xp reward is about 2.5k... for a party of 4 that takes them about 2/3 the way to level 2 already!

It just seems a little off to me...

Any help appreciated!

 

[Psilocybes]

EDIT: Didnt noticed you were talking about the EL also. I think the EL would be 1 also. But dont quote me on that.

I thought it would be a CR of 1.

6 (kobolds) * 1/6 (kobold CR) = 1

I dont have the book with me but this is how we do it in D&D and I dont think its changed.

 

[Magic Missile]

Yeah, that's how I did it in D&D too... 6 lots of 1/6 CR beasties = total CR 1...

But according to d20 modern, if all creatures have the same CR, you add a number based on the amount of creatures (table 7-6 says 2 creatures +2 CR, 3 creatures +3 CR etc.)... which is how I get my end EL of 6.

Still seems really high for 6 kobolds. I'm sure I've got something wrong somewhere, but the rules as I read them keep leading me to EL 6...

 

[HeapThaumaturgist]

Isn't it like ...

You take the EL of the first creature. Double it for the second. And double the EL again for every doubling after that?

So ... 1/6 for one Kobold. 1/3 for 2 Kobolds. 2/3 for 4 Kobolds. 1 1/3 for 8 Kobolds ...

I'm not looking at any books, mind you, this is just that I remember something working like that.

*blinky*

My memory is odd from time to time, and I'm on vacation and don't have my books.

--fje

 

[bwgwl]

i'd only use that table if the base CR of the creature is 1 or above.

for creatures with a base CR less than 1, i'd still do it the D&D way -- so six CR 1/6 kobolds are EL 1.