Damon Griffin
First Post
Re: how is this
No, this is not satisfactory. On any roll of doubles, you roll twice on the above table, yes? A roll of doubles, on d100, will occur 10% of the time. Once the above table is invoked, there is a 10% chance that a result of 1000 years will be rolled (2 trials, each with a 1 in 20 chance...2 in 20 = 1 in 10).
This means that 1 in every 100 mines of any kind are going to last for 1000 (plus up to 99 weeks.) An equal number of mines will only last for 1 year (plus up to 99 weeks). The lifetime of a mine ought to be weighted toward the lower end of the scale, but here it is not.
One in (1 in 10 * 1 in 20 * 1 in 20) every 4000 mines will last just over 2000 years. This is rare enough that I'd be inclined to say it's okay as it, but again, an equal number of mines will last for just over 2 years (you are just as likely to roll '11' twice on the above table as you are to roll '20' twice). There should be a LOT more mines that can he worked for 2 years plus 33 weeks than mines that can be worked for 2000 years plus 33 weeks.
Actually, it's probably not true that the greatest distribution occurs at the extreme low end of the scale. More likely this should be an asymmetrical bell curve, with results of -- I don't know, 5 years or 10 years? I haven't done the research on average life of a mine -- being the most likely result, with results becoming less likely as they drop toward 1d20 days, or toward 1000 years.
jasper said:Life time of the mine is determined by rolling D100 this is number of weeks it will last. On doubles roll twice on the following table and add to first result.
Life of mine (assume 1 man week)
D 20
1 days roll 1d20
2 days roll 2 d20
3-4 weeks roll 1 d20
5-6 weeks roll 2 d20
7-8 months roll 1 d20
9-10 months roll 2 d20
11 1 years
12 5 years
13 20 years
14 50 years
15 75 years
16 100 years
17 250 years
18 500 years
19 750 years
20 One thousands years
No, this is not satisfactory. On any roll of doubles, you roll twice on the above table, yes? A roll of doubles, on d100, will occur 10% of the time. Once the above table is invoked, there is a 10% chance that a result of 1000 years will be rolled (2 trials, each with a 1 in 20 chance...2 in 20 = 1 in 10).
This means that 1 in every 100 mines of any kind are going to last for 1000 (plus up to 99 weeks.) An equal number of mines will only last for 1 year (plus up to 99 weeks). The lifetime of a mine ought to be weighted toward the lower end of the scale, but here it is not.
One in (1 in 10 * 1 in 20 * 1 in 20) every 4000 mines will last just over 2000 years. This is rare enough that I'd be inclined to say it's okay as it, but again, an equal number of mines will last for just over 2 years (you are just as likely to roll '11' twice on the above table as you are to roll '20' twice). There should be a LOT more mines that can he worked for 2 years plus 33 weeks than mines that can be worked for 2000 years plus 33 weeks.
Actually, it's probably not true that the greatest distribution occurs at the extreme low end of the scale. More likely this should be an asymmetrical bell curve, with results of -- I don't know, 5 years or 10 years? I haven't done the research on average life of a mine -- being the most likely result, with results becoming less likely as they drop toward 1d20 days, or toward 1000 years.