randomling said:
OK so here's where we hit on-topic.
When you talk about the "average" roll of, say, 4d6, are we talking about a mean, median, or mode?
None of them. We are talking about the
expected value, which is like a mean but subtlely different.
The expectation of a discrete distribution (like 4d6) is calculated by multiplying each possible outcome by its probability of occurring, and then adding together the products.
If you roll 4d6
n times, sum the
n rolls, and divide by
n, you will have the mean of
those particular rolls. For given
n, that will be sometimes more and sometimes less: it will be a random variable (it is called the
sample mean, and its symbol is an X with a bar across the top). But if you make
n really big, the chances are very small that X-bar will be very far from
mu, where
mu is the expected value. (For discrete distributions, the expected value corresponds to a thing called the population mean, but the point is not extensible to continuous distributions, and tends not to get a lot of attention in real statistics.)
Example:
2d6 has eleven possible outcomes (2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12). Their probabilities are (1/36, 1/ 18, 1/12, 1/9, 5/36, 1/6, 5/36, 1/9, 1/12, 1/18, 1/36). Multiply each possible outcome by its own probability and you get (2/36, 6/36, 12/36, 20/36, 30/36, 42/36, 40/36, 36/36, 30/36, 22/36, 12/36). Add those up and you get 252/36 = 7. The expectation of 2d6 is 7.
Now I roll 2d6 eleven times and get (5, 4, 7, 11, 3, 8, 3, 9, 7, 8, 7). That sample has a mean of 6 6/11 (and it has a median of 7 and a mode of 7), but it doesn't have an expectation because it is a sample, not a distribution. Meanwhile, 2d6 has an expectation of 7, doesn't have a mean, and doesn't have a median, because it is a distribution, not a sample. (A distribution does have a mode, but in a slightly different sense from that in which a sample does. The mode of 2d6 is 7.)
Regards,
Agback