SRD has everything except...


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The SRD doesn't have rules for character generation and advancement -- that's one of the funky things about it.

But in order to reach the next level, you always have to earn your current level x1,000 in experience points.

To reach 12th level, you'll have to have earned 11,000 XP since you reached 11th level; before that, you earned 10k, and before that, 9k, etc.

I think it works out to 66,000 total.

Daniel
 


Storminator said:
level*(level-1)*500 in general

Cool! Your math-fu is stronger than my math-fu!

I just want to clarify that in your equation, "level"="level you're aiming for," not your current level. That threw me off at first when I was trying the formula out.

Otherwise, this is a much more elegant way to figure it out than my method.

Daniel
 


Drawmack said:
acctually it's n! * 1000 where n is the desired level.

i.e. 5! * 1000 = (5+4+3+2+1) * 1000 = 15,000

For some reason, I thought 5!=5*4*3*2*1. Oops! Anyway, your explanation is the same one I offered above, only in more mathematical terms; I think Storminator's explanation has the advantage of being easier to implement (since most folks find multiplication simpler than factorials)

Daniel
 

Pielorinho said:
For some reason, I thought 5!=5*4*3*2*1.

You probably thought that because it is. But we can get the point from his post, which is that there's a relatively simple method to determine it :)

Although he's also wrong, in that the formula is n?*1000 where n is your current level, not target level. (Where n? is the additive version of factorial, summational maybe.)

To get from 1st to 2nd, it's 1000, not 3000.
 
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DanMcS said:


You probably thought that because it is. But we can get the point from his post, which is that there's a relatively simple method to determine it :)

Although he's also wrong, in that the formula is n?*1000 where n is your current level, not target level. (Where n? is the additive version of factorial, summational maybe.)

To get from 1st to 2nd, it's 1000, not 3000.

And since the "summational" of n is n * (n + 1) / 2, it all works out...
 

CRGreathouse said:
And since the "summational" of n is n * (n + 1) / 2, it all works out...

Yes, yes, we all know that, but the other formula might have made more sense in someone's mind who wasn't math-tastic, so why not slap it into a shape where it's usable?
 


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