marcoasalazarm
Explorer
Well, this looks pretty good.
-
NOW LIVE! Into the Woods--new character species, eerie monsters, and haunting villains to populate the woodlands of your D&D games.
Venus World
- Thread starter Thomas Bowman
- Start date
Thomas Bowman
First Post
Thank you.
Explorers are sucked through the gate at the center of the Venus Polar vortex and crash land their airship near the Summit of this Mountain on Legendary Venus:
It is the tallest mountain on the planet, at the summit of which is a crystal palace, the abode of the goddess that controls the gate. The two astronauts get out of their airship and climb to the summit.
The airship is a wreck
The astronauts explore the crystal palace and set up a base of operations, as the only place they can contact their mothership and through that Mission Control is from the peak of this mountain, their host is missing, but someone set a table for them, and it appears it was set mere moments before they entered the palace, also found is a kitchen, a larder full of food, and several bedrooms. The peak of the mountain juts above the cloud deck, what lies below cannot be seen from up here. The goddess who set the table wishes to observe the two astronauts that have entered her residence without revealing herself to them just yet. She brought them here after all, that is what the gate was designed to do.
Thomas Bowman
First Post
I use these stats for Aphrodite's Avatar:
Its a depowered Avatar, the purpose of which is to inconspicuously mingle with the settlers without drawing too much undue attention, she appears as an 18-year old girl, very beautiful in appearance of course, she has the ability to cast clerical cure spells as if they were Bard or Sorcerer spells
Its a depowered Avatar, the purpose of which is to inconspicuously mingle with the settlers without drawing too much undue attention, she appears as an 18-year old girl, very beautiful in appearance of course, she has the ability to cast clerical cure spells as if they were Bard or Sorcerer spells
Thomas Bowman
First Post
Here is a map of the Inner System:
Using the Realistic Travel times for D20 Future under the column for PL6 Engine we have the following Travel Times:
Earth to the Moon (240,000 miles) 8 hours
Earth to the Sun (93,000,000 miles) 129.2 days
Earth to Mercury (56,950,000 miles 79.1 days
Earth to Venus (26,040,000 miles) 36.2 days
Earth to Mars (48,360,000 miles) 67.2 days
We get a travel rate of 3 million miles every 100 hours. (4 and 1/6 days).
30,000 miles per hour.
48,000 km per hour.
13,333 and 1/3 meters per second
Lets assume an acceleration of 1 meter per second, that is 3.7 hours to accelerate to this velocity for a total of 7.4 hours of acceleration time for a total distance traveled at an average speed of 15,000 miles per hour, of 111,000 miles the remaining miles to be covered is 129,000 miles, which at a rate of 30,000 miles per hour takes an additional 4.3 hours for a total travel time of 11.7 hours.
So using the formula: (Distance in miles - 111,000 miles) / 30,000 miles per hour + 7.4 hours = The travel time in hours.
One can find the distance in squares by the distance formula by counting the horizontal number of squares between two planets on the map, and then the vertical number of squares and then applying the Pythagorean theorem Distance = square root of the sum of the vertical distance squared and the horizontal distance squared or Distance = (x^2 + y^2)^0.5
A more legible map can be found at https://thomasbowman767.deviantart.com/art/Solar-System-Inner-725496454
The positions on the map can be used as the starting positions, the map I took them from shows the positions of the planets at the beginning of the year 2013, but for game purposes, you can either find the actual positions of the planets in the year 2078 or you can just use this map as is, however you like. We have a period for each orbit, so this gives you how many degrees to advance each planet for any given time period, or you can use Kepler's law of planetary motion, which states that a planet sweeps equal areas of its orbit in equal amounts of time. Area of a circle is Area = 2 pi radius^2. The period of the orbit of each planet is found at the corners of the map. Divide the area of a circle at the planet's average distance from the Sun by its orbital period in days, and that is the area swept out by each planet in one day, now use the current distance of the planet and calculate the distance covered by that planet when it sweeps an equal area of a circle drawn at the current distance. So if te current distance is greater than average, it will travel fewer degrees in one day, if it is closer, it will cover more degree in its orbit. All orbital motion on this map is counter-clockwise. Dotted line orbits indicate that portion of the orbit is below the plane of the ecliptic.
Earth to the Moon (240,000 miles) 8 hours
Earth to the Sun (93,000,000 miles) 129.2 days
Earth to Mercury (56,950,000 miles 79.1 days
Earth to Venus (26,040,000 miles) 36.2 days
Earth to Mars (48,360,000 miles) 67.2 days
We get a travel rate of 3 million miles every 100 hours. (4 and 1/6 days).
30,000 miles per hour.
48,000 km per hour.
13,333 and 1/3 meters per second
Lets assume an acceleration of 1 meter per second, that is 3.7 hours to accelerate to this velocity for a total of 7.4 hours of acceleration time for a total distance traveled at an average speed of 15,000 miles per hour, of 111,000 miles the remaining miles to be covered is 129,000 miles, which at a rate of 30,000 miles per hour takes an additional 4.3 hours for a total travel time of 11.7 hours.
So using the formula: (Distance in miles - 111,000 miles) / 30,000 miles per hour + 7.4 hours = The travel time in hours.
One can find the distance in squares by the distance formula by counting the horizontal number of squares between two planets on the map, and then the vertical number of squares and then applying the Pythagorean theorem Distance = square root of the sum of the vertical distance squared and the horizontal distance squared or Distance = (x^2 + y^2)^0.5
A more legible map can be found at https://thomasbowman767.deviantart.com/art/Solar-System-Inner-725496454
The positions on the map can be used as the starting positions, the map I took them from shows the positions of the planets at the beginning of the year 2013, but for game purposes, you can either find the actual positions of the planets in the year 2078 or you can just use this map as is, however you like. We have a period for each orbit, so this gives you how many degrees to advance each planet for any given time period, or you can use Kepler's law of planetary motion, which states that a planet sweeps equal areas of its orbit in equal amounts of time. Area of a circle is Area = 2 pi radius^2. The period of the orbit of each planet is found at the corners of the map. Divide the area of a circle at the planet's average distance from the Sun by its orbital period in days, and that is the area swept out by each planet in one day, now use the current distance of the planet and calculate the distance covered by that planet when it sweeps an equal area of a circle drawn at the current distance. So if te current distance is greater than average, it will travel fewer degrees in one day, if it is closer, it will cover more degree in its orbit. All orbital motion on this map is counter-clockwise. Dotted line orbits indicate that portion of the orbit is below the plane of the ecliptic.
Last edited:
Thomas Bowman
First Post
Here is my first PC starship for D20 Future
The assumptions are that there is no artificial gravity, a full tank of fuel will get this spaceship into Orbit from the Surface of the Earth or a smaller planet, and from Orbit, this ship can accelerate to 60,000 miles per hour and then slow down to a stop and do it one more time, this ship can only take off from a planet's surface once however. Once this ship enters a planetary atmosphere, it can maneuver at subsonic speeds using air from the air intakes as reaction mass, but to get into orbit again, it needs to fill its tanks with liquid hydrogen, the fusion torch drive is also a fusion reactor, although it can't maneuver within an atmosphere, it can provide power while within an atmosphere, it can power a thruster to get the ship back into orbit on a full tank of liquid hydrogen, it can also crack water into hydrogen and oxygen, and power an onboard refrigeration system to liquefy the hydrogen it collects and store it in its tanks.
A full size diagram of this ship can be found at https://thomasbowman767.deviantart.com/art/Ultralight-Scout-725873319?ga_submit_new=10:1516090169
A full size diagram of this ship can be found at https://thomasbowman767.deviantart.com/art/Ultralight-Scout-725873319?ga_submit_new=10:1516090169
Last edited:
Thomas Bowman
First Post
I know it doesn't look "ultralight", its as tall as a 17-story building on landing legs, but the rules state that if its no longer than 250 feet long, then its an ultralight spaceship, compared to some other possibilities, it is something the PCs might be able to afford, assuming they had a bank to finance it. It has a crew of four and can accommodate 4 passengers beyond that, that means each PC would have to finance $2,500,000 of it, a typically commercial bank would require about 10% down for a commercial loan, that would mean each PC would have to come up with $250,000 each to get that loan, if they each got second mortgages on their homes, that might cover it.
marcoasalazarm
Explorer
Awesome.
Thomas Bowman
First Post
Thank you.
Its part of a larger solar system which contains the planets that I call Legendary Earth and Legendary Mars. Politically the borders of Legendary Earth reflect the Earth during the 12th century.
Mars on the other hand looks like this:
Similar Threads
