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[d20] What don't you know? (free pdf books)

TheLe

First Post
[imager]http://www.thele.com/thelegames/images/html/quiz.gif[/imager]Welcome to The Le Games' What Don't You Know, our blatant rip off of a radio show of a simular name.

Every few days I will post a new question here in this thread. Whoever replies first with the correct answer will win a pdf book of his or her choice, from my library:
View List Here

Some books will be ineligible for a few months, like Unorthodox Paladins, coming in July (shameless plug).

I will reply to this thread when there is a winner, and email them for their prize.

I will post a new question on this thread every couple days. Please note that if you do NOT have the correct answer, I may just ignore your post until someone does have the right answer. All the questions have been carefully studied, while the answers may have not. All decisions are final. Winners of one week are not allowed to win in the same week (this is subject to change). So if you win, please give someone else a chance.

On to the first question:

At 12:00 pm, you find out that you have been poisoned while fighting an evil fungal creature! Your Archmage-friend gives you 7 antidote pills and says "You MUST take ONE pill every 30 minutes, or you will die".

What time will you take your last pill?




THE LE GAMES, WE ENHANCE WORLDS
 
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I assume you take one immediately, and then one each 30 minutes after that.

So:

1: 12:00pm
2: 12:30pm
3: 1:00pm
4: 1:30pm
5: 2:00pm
6: 2:30pm
7: 3:00pm

Of course, if we're talking D&D, after the first minute you're fine ... :)
 

whoohoo!

Patryn of Elvenshae said:
I assume you take one immediately, and then one each 30 minutes after that.
7: 3:00pm

Of course, if we're talking D&D, after the first minute you're fine ... :)

Wow. That was quick. Some 30 views before a correct answer too. Congrats, Patryn of Elvenshae. That is correct, it would be 3pm. Alot of people forget about taking the first pill immediately.

Please Private-message me with your book selection, and I will have rpgnow.com fire it off to you. I tried to PM you, but you have it turned off. And I cannot seem to email you.

That was too quick. I will put up a new quiz tonight. Please let someone else get a chance to win tonight!

`Le
 

Heh - you can't PM me because I'm not a paid member. My e-mail address is:

ELVENSHAE ... AT ... YAHOO ... DOT ... COM. (Take that, spamhunters!)

At any rate:

SWEET! I won something! How cool is that? :D

I'll be sending you my choice in a few moments, after I peruse a bit more of your catalog. :D
 

New Quiz!

[imager]http://www.thele.com/thelegames/images/html/quiz.gif[/imager]Okey. New Quiz! The prize is the same -- one pdf of your choice from my collection to the first person to post a correct answer. The previous winner is not eligable.


QUIZ:
The Dragon shows you a weight scale (the kind with 2 arms), then he hands you 9 small, glowing spheres. He says "Of these nine stones, one is slightly heavier than the others. Show me the quickest way to find this heavier stone."

You must use the scale to answer this riddle.



--THE LE GAMES, WE ENHANCE WORLDS
 


Put three stones on the left arm and three on the right. If one side is heavier, then the heavy stone is on that side. If the two sides weight the same, the heavy stone is one of the three left out. The possibilities for the heavy stone are now narrowed down to 3.

Of the remaining three, put one on the left arm of the scale and one on the right. If one side is heavier, it holds the heavy stone. If the arms are even then the stone left over is the heavy one.
 

thele said:
QUIZ:
The Dragon shows you a weight scale (the kind with 2 arms), then he hands you 9 small, glowing spheres. He says "Of these nine stones, one is slightly heavier than the others. Show me the quickest way to find this heavier stone."

You must use the scale to answer this riddle.
Place 4 stones on either side of the scale. If the weight is equal, the "odd one out" is the heavier stone.

If the weight is different, remove all stones from the scale. Take the 4 stones from the heavy side and place 2 on either side of the scale. When you do this, one side will be heavier than the other.

Remove all stones from the scale, and place the one stone from the heavy side on each side of the scale. The side that is heavier contains the heavy stone.

A maximum of three weighings is required, and guarantees the correct stone.

I note the post above me requires a maximum of two weighings... so it must be the correct answer, not this one.
 

Hmm. That's only 3 weighings, but if they weren't even, I'd just swap the one out that I am holding with the heavy side until they were... and then I'd be hoding the heavy one. I guess that's technically more weighings, but my back would be happier about the situation. ;)
 
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Wiinnnerr!

Mishihari Lord said:
Put three stones on the left arm and three on the right. If one side is heavier, then the heavy stone is on that side. If the two sides weight the same, the heavy stone is one of the three left out. The possibilities for the heavy stone are now narrowed down to 3.

Of the remaining three, put one on the left arm of the scale and one on the right. If one side is heavier, it holds the heavy stone. If the arms are even then the stone left over is the heavy one.

YEESSSS... you are correct sir. That allows for a maximum of 2 iterations on the scale.

Please let me know your prize choice, and email and I will fire it off to you. Or email me at The Le Games (@t) yahoo

Good work. New quiz tomorrow.

~Le
 

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