Lord Zardoz
Explorer
Just a random thought.
I know that for a Jump check, if your check result exceeds your permitted movement, you have to complete the movement in the next round, (essentially ending the round in mid jump).
Is there a corresponding rule for falling? Or does a character fall at essentially the speed of light. I suppose such a scenario could be used as a set up for a fight between a player and a villain over a potion of feather fall (Someone must win a grapple and drink it before X rounds is up, otherwise both get to go splat).
I know this can be worked out mathematically, but doing so would cause the movement rate to increase as the player fell. This is D&D, not a Newtonian physics simulator. Still, for those who are curious..
gravity=9.8 m/s^2
D&D terminal falling damage = 20d6 == 200 feet == 60.96 m
60.96 = 9.8 * (time)^2;
sqrt(60.96 / 9.8) = time
2.49407461 seconds = time
so to convert 200 ft of movement taking 2.49407461 seconds into 6 seconds of movement..
6 / 2.49407461 = 2.40570189
200 * 2.40570189 = 481.140378
So a falling rate of 480 or 96 squares in the first round (unless I screwed part of the math). Seems a bit much for D&D for my tastes. Is there a better / more official number out there?
END COMMUNICATION
I know that for a Jump check, if your check result exceeds your permitted movement, you have to complete the movement in the next round, (essentially ending the round in mid jump).
Is there a corresponding rule for falling? Or does a character fall at essentially the speed of light. I suppose such a scenario could be used as a set up for a fight between a player and a villain over a potion of feather fall (Someone must win a grapple and drink it before X rounds is up, otherwise both get to go splat).
I know this can be worked out mathematically, but doing so would cause the movement rate to increase as the player fell. This is D&D, not a Newtonian physics simulator. Still, for those who are curious..
gravity=9.8 m/s^2
D&D terminal falling damage = 20d6 == 200 feet == 60.96 m
60.96 = 9.8 * (time)^2;
sqrt(60.96 / 9.8) = time
2.49407461 seconds = time
so to convert 200 ft of movement taking 2.49407461 seconds into 6 seconds of movement..
6 / 2.49407461 = 2.40570189
200 * 2.40570189 = 481.140378
So a falling rate of 480 or 96 squares in the first round (unless I screwed part of the math). Seems a bit much for D&D for my tastes. Is there a better / more official number out there?
END COMMUNICATION
. As you've shown for the 1st round, and 1000 ft/6 seconds is a reasonable terminal velocity for most objects.
