UngeheuerLich
Legend
I actually think my first idea was better:Asmor said:I was thinking of the same problem... The parity between required successes before failures (always 2:1) does seem to skew the math.
I think the way I might implement it is to make a set number of failures, regardless of complexity. I'm thinking 4.
So a complexity 1 encounter requires 4 successes before 4 failures. A complexity 2 encounter requires 6 successes before 4 failures. etc.
EDIT: Looks like UngeheuerLich had the same idea. Great minds!
X successes before more than x/2 failures... getting 12 successes before 4 failures seems too hard!