What is the EL of this encounter?

[Xar666]

Karn: Male ogre Ftr2; CR 4; Large Giant; HD 4d8+16+2d10+8; hp 53; Init +0; Spd 20 ft.; AC 21; Atk +14 melee (2d8+13/19-20/x2 crit, MW Fullblade) +5 ranged (1d8+4/x3 crit, Mighty Composite Longbow +4); AL CE; SV Fort +11, Ref +1, Will +0; Str 28, Dex 10, Con 18, Int 8, Wis 9, Cha 8.
Skills and Feats: Climb +13, Hide –4, Jump +12, Listen +4, Move Silently +0, Spot +4; Power Attack, Sunder, Improved Sunder
Possessions: Large Half-plate; MW Fullblade; Mighty Composite Longbow +4; 20 arrows

Rast: Male human Rog2; CR 2; Medium-size humanoid (human); HD 2d6+2; hp 12; Init +4; Spd 30 ft.; AC 20; Atk +5 melee (1d6+3/18-20/x2 crit, MW Rapier) +6 ranged (1d6+2/x3 crit, MW Mighty Composite Shortbow +2); AL CE; SV Fort +2, Ref +7, Will -1; Str 17, Dex 18, Con 14, Int 14, Wis 9, Cha 12.
Skills and Feats: Bluff +6, Climb +6, Disable Device +7, Escape Artist +7, Hide +7, Jump +6, Listen +4, Move Silently +7, Search +7, Spot +4, Tumble +7; Expertise, Improved Trip
Possessions: MW Chain Shirt; MW Rapier; MW Mighty Composite Shortbow +2; 20 arrows; Potion of Cure Light Wounds

Keelor: Female human Rog2; CR 2; Medium-size humanoid (human); HD 2d6-1; hp 9; Init +4; Spd 30 ft.; AC 18; Atk +5 melee (1d6+3/18-20/x2 crit, MW Rapier) +6 ranged (1d6+2/x3 crit, MW Mighty Composite Shortbow +2); AL CE; SV Fort -1, Ref +7, Will -2; Str 17, Dex 18, Con 8, Int 13, Wis 6, Cha 11.
Skills and Feats: Bluff +5, Climb +7, Disable Device +6, Hide +9, Listen +5, Move Silently +9, Search +8, Spot +5, Tumble +9, Point Blank Shot, Precise Shot
Possessions: MW Chain Shirt; MW Rapier; MW Mighty Composite Shortbow +2; 20 arrows; Potion of Cure Light Wounds

Also, Do you think it is too tough for the following party:

Rog3/Ftr2
Ftr3/Rgr2
Cleric6
Paladin4

 

[Ridley's Cohort]

Seems about right.

The Ogre is not that much tougher than a regular Ogre. He alone is no worse than 2 normal Ogres with the exception that he has a nice ranged attack. CR 4 sounds right.

The sunder feats will be a nasty surprise IF he has a magic weapon to match up against the PCs. (Weaker weapons cannot sunder magically stronger ones.)

The Rogues are goners to a Hold Person spell. Of course with their HPs it is probably not even worth spending a spell.

The Party is equivalent to level 5. So a CR 4 with a couple little twerps is about right.

 

[trentonjoe]

seems okay to me too.

A 4 and two 2's is an EL 6 I think. I think it would drain about 50% of your parties resources.

 

[Leopold]

according to the Encounter calculator it is:


Encounter Level -6
Difficulty Factor -.9
Difficulty -Challenging
Advice To Party -Keep On Your Toes.


I don't think they will have a problem with it.

 

[twjensen]

encounter calculator?

according to the Encounter calculator it is:


Encounter Level -6
Difficulty Factor -.9
Difficulty -Challenging
Advice To Party -Keep On Your Toes.


I don't think they will have a problem with it.

Is this something in the DMG I missed or is this an on-line thing?

 

[Thanee]

online thing.

I'm sure someone also knows the link!

Bye
Thanee

 

[Steven McRownt]

The encounter calculator works even off line, so here's the attachment with the html...
...no wait, no html attachment could be made with this messageboards:

so, here comes a zipped (because even RAR is not welcome here!) version of it

Steven McRownt

 

[Thanee]

The encounter should be no problem for the party, if they don't make stupid mistakes!

The Cleric alone should be able to beat these three in a straighforward fight!

Bye
Thanee

 

[Al]

Looks about EL5/6 to me, so should be fine for the party.

The only tricky one could be the ogre: he's dishing out a lot of damage, isn't subject to Hold Person, has a fair few HPs and respectable AC.
The rogues are pathetic: the fighters could easily dispatch them in one or two hits, but they add a little spice.

Still, once the rogues are gone, the whole party should be able to concentrate on the ogre and despatch him without too much bother.

 

[AGGEMAM]

Xar666, to calculate the EL you need to have the CR, which you do, then if you have two monsters with equal CR and the CR is above 1, add two to their combined CR. Keep doing this until you only have one combined CR, then that is equal to the EL

In your case you have two CR 2 monsters, their combined CR is 4.
Now you have two CR 4 monsters, the total combined CR is 6.
So the EL is 6.