L
lowkey13
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My preferred method of rolling for players is 4d6, drop lowest one, roll eight times, drop second lowest score, then arrange (sometimes I have them not arrange, and it's in order, but with the second lowest score still dropped).
Thoughts on this-
I think random is good.
It generally results in overall higher ability scores, which players like for the feeling of heroism. (That said, straight out 18 are still fairly rare, although 17s do pop up pretty often).
The extra roll biases in favor of slightly good scores.
Having players keep their *worst* roll ensures that most players will have one "bad" ability.
I have kept this since 1e and BECMI (it was an evolution to this). That said, I don't play with feats, so I don't worry about that. I have noticed that the added ability improvements at certain levels have allowed players to hit "20" in core abilities. I'm not sure how I feel about that so far; I haven't run 5e enough to have a full opinion.
Not exactly. If you do out the math, you'll find that the odds of rolling a 17 are roughly 3x the odds of rolling an 18 (a little more than 4% as opposed to ~1.5%). You also have a litle more than a 17% chance of rolling a 15 or 16.
(Why? Math. You're also missing that you're dropping a die, and the 5 can occur on any of the independent rolls, whereas a 6 must occur on 3 of the four rolls- 5,6,6, 6,5,6, 6,6,5).
Okay- have you actually run the distribution? Have you looked at the percentages? What I told you is factually correct. But let's use a quick example of rolls-
1 6 6 6
2 6 6 6
3 6 6 6
4 6 6 6
5 6 6 6
6 6 6 6
1 5 6 6
1 6 5 6
1 6 6 5
2 5 6 6
2 6 5 6
3 6 6 5
Are you starting to see a pattern? This is pretty easy to program, if you want to run it, say, a million times and see the actual frequency that comes up.
No, it doesn't. Because you don't deop the forth, you drop the lowest. Which means you only drop a 6 if you've 4 sixes. The sixes will always be the non-discarded numbers by their very nature as the highest number possible.EDIT- I saw your numbers- you keep missing that the 5 can be any of the three numbers; the six *must* be all of the non-discarded numbers.