Sorry, at work (away from books) and another guy and I are debating over magic item creation rules back in forth in email.
1) can anyone clue me in on or point me to the source that gives the max gold value of magic items? I know the max enchantment is +10 for arms and armor (200K and 100K gp respectively) - but isn't there a gold piece limit as well?
IE: +10 mithral fullplate, greater silent moves, greater slick, greater shadow, greater resistance, blueshined, and greater stamina would run something like; 100,000 + 10,500 +33,750 +33,750 +33,750 +66,000 +1,500 +8,000 = 287,250gp (numbers might be off slightly but you see what I mean)
2) adding additional enchantments to an item in an unusual location, how's the math work on this?
say you want to add +2 Str to Boots of Springing and Striding; from what we 'think' we know adding an additional enchantment should run x1.5 the cost.
Ok, simple enough.
But now adding an additional enchantment in an unusual location should be x2 the cost.
So how does D&D math work when adding and additional enchantment in an unusual location?
would it be the (4K x 1.5) x2 = 12K
or
(4K x 1.5) + (4K x 2) = 14K
or
([1]base + [.5]extra enchant) + ([1]base + [1]unusual loc) = [1]base + [1.5]extra & unusual = X2.5 total = 10K
...Thanks...
1) can anyone clue me in on or point me to the source that gives the max gold value of magic items? I know the max enchantment is +10 for arms and armor (200K and 100K gp respectively) - but isn't there a gold piece limit as well?
IE: +10 mithral fullplate, greater silent moves, greater slick, greater shadow, greater resistance, blueshined, and greater stamina would run something like; 100,000 + 10,500 +33,750 +33,750 +33,750 +66,000 +1,500 +8,000 = 287,250gp (numbers might be off slightly but you see what I mean)
2) adding additional enchantments to an item in an unusual location, how's the math work on this?
say you want to add +2 Str to Boots of Springing and Striding; from what we 'think' we know adding an additional enchantment should run x1.5 the cost.
Ok, simple enough.
But now adding an additional enchantment in an unusual location should be x2 the cost.
So how does D&D math work when adding and additional enchantment in an unusual location?
would it be the (4K x 1.5) x2 = 12K
or
(4K x 1.5) + (4K x 2) = 14K
or
([1]base + [.5]extra enchant) + ([1]base + [1]unusual loc) = [1]base + [1.5]extra & unusual = X2.5 total = 10K
...Thanks...
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