EzekielRaiden
Follower of the Way
Assume E is the expected value of a rolled exploding dN die, which explodes infinitely often when you roll N.Does it? How did you arrive at that? Is this exploding once or every time you roll the max value, because the latter does feel off at a minimum.
This means E = 1/N(1)+1/N(2)+...+1/N(N+E). You might think this becomes insoluble, but it's actually quite soluble.
E=(1/N)(1+2+...+N)+(1/N)E
Note: sum of first N integers is (N)(N+1)/2. So, simplify that sum, and subtract (1/N)E from both sides.
E-(1/N)E = (1/N)(N)(N+1)/2
The division by N cancels out on the right, and we can combine the E terms on the left.
E(N-1)/N = (N+1)/2
E = N(N+1)/(2N-2)
So, for an infinitely exploding d4, the expected value is (4)(5)/(8-2) = 10/3 = 3.333....