So in the case of a CR 20 monster teamed up with 5 CR 10 monsters, you would dismiss the CR 10 creatures in assessing the encounter's difficulty?
Depends on the Party (which you have omitted). I have to decide if those CR 10 monsters significantly contribute to the threat of the encounter
to the party (and relative to the CR 20) to warrant multiplication at step 4.
It's quite likely they would pose a relevant threat to most parties, so I'd likely count them for multiplication purposes.
In our specific case, the monsters are CR 1/2, the party ae 7th level (and quite capable of taking a dozen out
with a single action via Fireball, Hypnotic pattern or similar) and they're significantly lower in challenge rating than the other monsters.
CR 1/2 monsters do not significantly contribute to the threat of that encounter to a 7th level party. They're likely slaughtered within a round or two at most. As I've already pointed out, Hypnotic pattern or Conjure animals mostly takes care of them (and each of the two primary casters have 4 slots of 3rd level or higher), and our Barbarian/ Fighter could literally take on a dozen on his own, mopping them up in 4-5 rounds with a use of Rage and an Action surge.
They're Mooks. Minions. Extras. They buy the high CR 'Boss' a round or two of extra attacks.
I would not individually count them at step 4. Instead, I'd treat them as a single monster (so for example, a single CR 3, and 6 x CR 1/2s vs this a party of 7th level PCs gets a x1.5 XP multiplier instead of a x2.5 multiplier).
It's a subjective call, relative to your party (and their strengths and weaknesses) and not a 'strictly applied mathematical formula'.