D&D 5E Artificers, Paladins, and Rangers, oh, MY! (Concerning Cantrips)


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It always works. Do the math.

Math teacher here.
Maybe I misunderstood you. Also math teacher here.
Can you write it down as formula?

I would say, you need to add 1 before rounding down, not 1/2.

(x+1)/2 round down should be the same as x/2 round up.

For x = 1 you get 1, for x = 2 you get 1, for x = 3 you get 2 in both cases, and so on.

y/2 round down should be one lower every other level.

For y = 1 you get 0, for y = 2 you get 1, for y = 3 you also get 1 and so on.

So if your artificer/ranger/paladin level is even, you don't round at all, so you get the same multiclass spellcaster level.
 

o if your artificer/ranger/paladin level is even, you don't round at all, so you get the same multiclass spellcaster level.
Half casters only advance every other level. So the casting ability of a 4th level ranger is exactly the same as a 5th level ranger. So, whist it is true that a 4th level artificer has the same casting ability as a 4th level ranger, it is also true that they have the same casting ability as a 5th level ranger. I.e ranger level +1, as I stated.

It's a bit tricky for me to type some symbols (such as modulus), but it's ECL = mod((L+1)/2); ECL is the effective caster level, L is the artificer's level.
 
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Half casters only advance every other level. So the casting ability of a 4th level ranger is exactly the same as a 5th level ranger. So, whist it is true that a 4th level artificer has the same casting ability as a 4th level ranger, it is also true that they have the same casting ability as a 5th level ranger. I.e ranger level +1, as I stated.

It's a bit tricky for me to type some symbols (such as modulus), but it's ECL = mod((L+1)/2); ECL is the effective caster level, L is the artificer's level.

But artificers and rangers have exactly the same spellcastin progression, except for level 1 and cantrips.
 

Half casters only advance every other level. So the casting ability of a 4th level ranger is exactly the same as a 5th level ranger. So, whist it is true that a 4th level artificer has the same casting ability as a 4th level ranger, it is also true that they have the same casting ability as a 5th level ranger. I.e ranger level +1, as I stated.

It's a bit tricky for me to type some symbols (such as modulus), but it's ECL = mod((L+1)/2); ECL is the effective caster level, L is the artificer's level.
Just because 'hey, who doesn't love a pedant?', the modulo operator is typically written as %.
 



That is the notation for absolute value... which is sometimes called modulus. You are using a modulo operator in the sense of obtaining a remainder when X is divided by a modulus Y.
You are probably right - I teach maths by default, my main subject is physics (and to be honest I scraped through the maths modules!)

My maths isn't as bad as my chemistry though, and I have to teach that too!
 

You are probably right - I teach maths by default, my main subject is physics (and to be honest I scraped through the maths modules!)

My maths isn't as bad as my chemistry though, and I have to teach that too!
I wasn't trying to give you a hard time! I'm a software engineer. I have (very infrequently) have made use of the modulo operator (which, as I was saying earlier, is usually written as % in the programming languages I frequent) so have inadvertently become aware of the intricacies of the term 'modulus' (although I'm sure some actual mathematician will come along and out-pedant/correct me on some of the finer points!).

I spent part of my university career studying Chemical Engineering... don't ask me to recall any of it though :)
 

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