What would the hardness and hitpoints of a 12-foot diameter spherical boulder be?

dead

Adventurer
Just wondering what the hardness and hitpoints of a 12-foot diameter spherical boulder would be?

I ask because in the free WotC adventure called "A Question of Ethics" by Monte Cook, there is a Wizard's Challenge in it where the above boulder is rolled down a hill and whoever destroys the boulder first wins the prize.

Now, you get points for *style*, too, and the three featured NPC wizards participating in the challenge use the following tactics:

1) Lightning Bolts
2) Summoning Thoqquas to destroy boulder
3) Disintergrate

Now, with the first 2, hardness and hitpoints of the boulder will play a factor, so I just wanted to get other folk's personal opinion on what these figures would be.

P.S. As a side note . . . wouldn't those poor Thoqqua's getted squashed? The boulder is surely size large and would perform an overrun action . . . What would the boulders overrun bonus be?
 
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DMG says hewn stone is hardness 8, hp 540 for 10x10x5 ft thick. Multiply by 4 (12 ft. thick) and you get -- hardness 8, hp 2,160.

Clearly some of those wizards have better tactics than others for different challenges (I read that adventure a week ago or so). A rolling boulder wouldn't count as an "Overrun" attack, you'd have to call it a trap at best (as falling block or something, likely easy to dodge if seen and rolling in a straight line).
 

Solid granite weighs 161 pounds per cubic foot.

A sphere 12' in diameter contains 452.376 cubic feet of granite, and weighs 72832.536 pounds, or 36.41 tons.

It's gonna have a LOT of hit points, espicially if you factor in the fact that in this case the participants don't simply have to break the boulder, they have to utterly demolish it.
 

Thanks for the help. :)

Wow, the wizard's who use lightning bolt and summon Thoqquas don't stand a chance.

The boulder would roll straight down the hill (I'm guessing it'd take 3 rounds tops) and mow into the surrounding crowd causing many spectator deaths. :confused:

Hmm. What other means besides disintergrate (and wish!) could you use to *realistically* destroy this thing coz obviously spells like lightning bolt and thoqqua attacks are gonna do nuthin!
 

Uh, Transmute Rock to Mud? :)

ETA:

Stone to Flesh it, and then Fireball it?

Summon an Earth Elemental using the rock as your material component?

Open a portal to the Plane of Fire in front of it?
 
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A 10x10x5 section of hewn stone has a volume of 500 cubic feet and 540 hp. That is 1.08 hp per cubic foot. The volume of the sphere is 4/3 pi x r^3, or about 905 cubic feet in case of 6 foot radius. That figures out to 977 hp, hardness 8 (same as hewn stone wall).

The disintergrate description in the 3.5 SRD says "When used against an object, the ray simply disintegrates as much as one 10- foot cube of nonliving matter." 10^3 is 1,000 cubic feet of volume. The sphere doesn't quite fit in a 10' cube, but it wouldn't leave much left (and I don't want to get into even more math).

The lightning bolt is significantly less productive. "Electricity and fire attacks deal half damage to most objects; divide the damage dealt by 2 before applying the hardness." That mage isn't going to have enough to destroy the boulder.

When I played this module, I polymorphed into the assassin demon from the MMII (I forget the name), stone shaped the ground as the boulder came down into a ramp, and attacked it with a greatsword as it flew over me. It wasn't very fast, but I did get style points.
 


Patryn of Elvenshae said:
Uh, Transmute Rock to Mud? :)

A perfectly spherical boulder was probably shaped that way by man. Thus it'd probably be considered *worked stone* and thus the spell would be useless against it. ;)

If I wanted a boulder with 100hp (giving the lightning bolts a fighting chance) how big would it be? The size of a basket ball?
 


dead said:
A perfectly spherical boulder was probably shaped that way by man. Thus it'd probably be considered *worked stone* and thus the spell would be useless against it. ;)

You didn't say it was perfectly spherical.

I assumed it was just a rather large, round rock that happened to be in the right place at the wrong time. :)

The other suggestions still work, though, if you're going with the worked stone ruling.
 

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