Spatzimaus
First Post
babomb said:Brute force isn't pretty, but it always works, at least.![]()
To paraphrase a quote from the Vietnam eta:
"If brute force doesn't solve your problems, you're obviously not using enough."
babomb said:Brute force isn't pretty, but it always works, at least.![]()
Coredump said:I think you have this a bit backwards. I would counsel against raising the median above 50. In fact, the original 20-12-10-8 seems about perfect. It is hard to have a 'very bad' wand experience, but almost all of them will be above 50, and some way above.
Coredump said:Not quite. The odds *are* exactly even with the 20-12-10-8 method; that means that the PC's will eventually come out....exactly even. By adding a D6 and D4, that means that the PCs will eventually come out...20% ahead. (60 charges per wand.)
20-12-10-8 means that most will be in the 40-50 range, some a little lower, some a lot higher, eventually balancing out to 50.
20-12-10-8-6-4 means that most will be in the 50-60 range, some a little lower, some a lot higher, eventually balancing out to 60.
The original method makes it a bit of a gamble, but still a very fair gamble. The second method makes it a no-brainer, and the PC's will almost always come out ahead, and on average quite a bit ahead.
Coredump said:Well, I think you have the 'quickly' part a bit off, but I do think it 'speading up' is part of the fun. You have to be careful when you are on the 'last die'
Spatzimaus said:Edit: Got the d6 numbers. Took a little under three hours to run, so there's no way I'm spending two weeks working out the d4 numbers.
10 or less now only happens 0.14%.
20 happens 3.6%.
30 happens 14.5%
40 happens 31.0%
50 happens 48.5%
60 happens 63.8%
70 happens 75.7%
80 happens 84.1%
90 happens 89.9%
and you have just under a 6% chance to make it past 100.
Median was 50.894. Mean was 56.
So actually, the 5-die progression ending with the d6 seems best to me; the mean's slightly higher than before, the median is right on 50, and the chances of a really short-duration wand go way down without drastically increasing the top end. Adding the d4 would be a bit much, IMO, pushing the median to 54ish and the mean to 60, but you COULD do it.
Agback said:Do you really have the million? Are you prepared to put it in escrow? Because you are offering better odds than any lottery, and millions of people buy tickets in million-dollar lotteries every week.
Agback said:Agback said:d6 = price of three scrolls of the spell. (Yes, at this point I'd start treating it as a semi-scroll)
d4 = price of two scrolls of the spell
Those last two are good buys!
Not quite. For example, it is more likely you will get 70 charges than 30 charges, and more likely to get 100 charges than 20 charges.ARandomGod said:Very bad and very good will be, of course, equally unlikely.
Sort of.... assuming you are talking about the 20-12-10-8-6 version... you will have a lot more way above compared to way below. It is not an even distribution about the median. Sticking with the 20-12-10-8-6 method is almost always going to lead to an overall power up. Again the 'winners' will be higher than the 'losers are low. So if 4 of 10 are betwenn 45-55, then one will be at 42 and one at 39, one at 35, and one at 65 and one at 85, and one at 95.However excatly 50% of in infinite amount of them will be below 50, some way below.
I would still recommend looking at the 20-12-8-6-4 method. It will give 50 charges per wand (on average), and give you the 'last minute' edginess of having the D4. While it is likely not a game breaker, I don't see why folks want to give out more than 50 charges per wand.Ah, well, the poor D4 gets left out, but this does look closer to what I personally wanted to see. The D4 probably is taking it a little over the top. Mainly I just thought it would be a good idea to favor "the house" a little, and assume that the wand users ARE "the house". Or else why are these wands made rather than the standard charged ones? (Ok, because the standard ones are removed, of course. But still).
Study it as economics, and not math. The 'opportunity cost' of a dollar just isn't that much, but the potential payoff.... Now, the ones I don't understand are those spending 50-100-150 dollars a *week* on lottery tickets.It's true, they do. Of course, in my statistics class we referred to that as "Tax on the mathematically impared".
Coredump said:I would still recommend looking at the 20-12-8-6-4 method. It will give 50 charges per wand (on average), and give you the 'last minute' edginess of having the D4.
Study it as economics, and not math. The 'opportunity cost' of a dollar just isn't that much, but the potential payoff.... Now, the ones I don't understand are those spending 50-100-150 dollars a *week* on lottery tickets.
Coredump said:Sort of.... assuming you are talking about the 20-12-10-8-6 version...
Coredump said:I would still recommend looking at the 20-12-8-6-4 method. It will give 50 charges per wand (on average), and give you the 'last minute' edginess of having the D4. While it is likely not a game breaker, I don't see why folks want to give out more than 50 charges per wand.
Coredump said:Study it as economics, and not math. The 'opportunity cost' of a dollar just isn't that much, but the potential payoff.... Now, the ones I don't understand are those spending 50-100-150 dollars a *week* on lottery tickets.
Spatzimaus said:Absolutely. When you're spending a small amount, the impact on your lifestyle is negligible. A few bucks a week is nothing for that, even when you total it up over several years, and if you were to actually WIN, you'd be set for life. And there are a couple thresholds to that, too; for many people, winning 100 million dollars isn't 10 times as good as winning 10 million. In both cases, you move into the "set for life" category. So it's clearly not a linear function.
ARandomGod said:He's occasionally won small amounts. Probably as much as 150 all together. In that time I've "won" 520. So far I'm ahead 370. And the odds are I'll keep getting farther and farther ahead.
Few people in my game groups buy/use wands. It just feels like you're throwing money away when you're buying something that you know will be gond soon
The non-linearity of the marginal value of income is crucial to explaining risk-taking behaviour. Unfortunately, risk-averse behaviour is consistent only with a diminishing marginal value of income, and risk-loving behaviour is consistent only with an increasing marginal value of income. Which suggests that a rational person would not both insure and gamble unless their marginal value of income were increasing for values of income above their actual income and ecreasing for values below it. I can't think of any reason why such a great many people should be stuck near the minimum of their marginal-vlue-of-income curve. So i am reluctantly forced to consider such hypotheses as a systematic mis-perception of risk.Spatzimaus said:So it's clearly not a linear function.